我正在尝试使用Java中的Rally REST API创建缺陷。

我插入缺陷的代码如下所示:

    JsonObject newDefect = new JsonObject();

    newDefect.addProperty("Workspace", workspaceRef);
    newDefect.addProperty("Project", projectRef);

    newDefect.addProperty("Name", d.name);
    newDefect.addProperty("Description", d.description);
    newDefect.addProperty("Notes", d.notes);
    newDefect.addProperty("Owner", getUserReference(restApi, d.owner));

    System.out.println("Creating defect: " + d.qcid + " - " + d.name);
    CreateRequest createRequest = new CreateRequest("defect", newDefect);
    CreateResponse createResponse = restApi.create(createRequest);


getUserReference的实现如下:

private String getUserReference(RallyRestApi restApi, String name) throws Exception
{
    // Read User
    QueryRequest userRequest = new QueryRequest("User");
    userRequest.setFetch(new Fetch("UserName", "Subscription", "DisplayName"));
    userRequest.setQueryFilter(new QueryFilter("UserName", "=", name));
    QueryResponse userQueryResponse = restApi.query(userRequest);
    JsonArray userQueryResults = userQueryResponse.getResults();
    JsonElement userQueryElement = userQueryResults.get(0);
    JsonObject userQueryObject = userQueryElement.getAsJsonObject();
    String userRef = userQueryObject.get("_ref").toString();
    return userRef;
}


问题:用户收到错误“无法解析对象引用”。当我使用实际名称([email protected])或如上所述的用户参考时,就会得到它。

我得到的当前错误是:无法从““ https://rally1.rallydev.com/slm/webservice/v2.0/user/14659049875”“解析对象引用

我究竟做错了什么?

谢谢
阿萨夫

最佳答案

请使用getAsString方法而不是toString。

尝试:

String userRef = userQueryObject.get("_ref").getAsString();


代替

String userRef = userQueryObject.get("_ref").toString();

10-07 16:10