javascript - 通过2个匹配属性从对象数组中删除重复项

当键值“ hour_from”和“ hour_to”相同时，我试图从字典中删除重复的元素。我正在使用double（我不记得要使用其他成本更低的算法了），但是索引值存在问题。

var hours_array = [
{day: "Mon", hour_from: "00:00", hour_to: "00:00"},
{day: "Mon", hour_from: "00:00", hour_to: "00:16"},
{day: "Mon", hour_from: "00:00", hour_to: "00:16"},
{day: "Thu", hour_from: "00:00", hour_to: "00:25"},
{day: "Mon", hour_from: "00:00", hour_to: "00:33"},
{day: "Fri", hour_from: "00:00", hour_to: "00:83"},
{day: "Sat", hour_from: "02:00", hour_to: "05:33"},
{day: "Thu", hour_from: "02:00", hour_to: "05:33"},
{day: "Wed", hour_from: "12:00", hour_to: "14:00"},
{day: "Sun", hour_from: "22:25", hour_to: "13:45"}]

for (let i=0; i< hours_array.length; i++){
 for (let j=0; j<=hours_array.length; j++){
  if ((hours_array[i]['hour_from'] == hours_array[j]['hour_from']) && (hours_array[i]['hour_to'] == hours_array[j]['hour_to'])){
  delete hours_array[j];
  }
 }
}

我认为索引值有误：



编辑：所需结果：

var hours_array = [
{day: "Mon", hour_from: "00:00", hour_to: "00:00"},
{day: "Mon", hour_from: "00:00", hour_to: "00:16"},
{day: "Thu", hour_from: "00:00", hour_to: "00:25"},
{day: "Mon", hour_from: "00:00", hour_to: "00:33"},
{day: "Fri", hour_from: "00:00", hour_to: "00:83"},
{day: "Sat", hour_from: "02:00", hour_to: "05:33"},
{day: "Wed", hour_from: "12:00", hour_to: "14:00"},
{day: "Sun", hour_from: "22:25", hour_to: "13:45"}]

有什么建议吗？
还有一些更有效的算法吗？
谢谢阅读！

最佳答案

您可能会随同Array.prototype.reduce()和Array.prototype.find()一起走懒。

const src = [{day:"Mon",hour_from:"00:00",hour_to:"00:00"},{day:"Mon",hour_from:"00:00",hour_to:"00:16"},{day:"Mon",hour_from:"00:00",hour_to:"00:16"},{day:"Thu",hour_from:"00:00",hour_to:"00:25"},{day:"Mon",hour_from:"00:00",hour_to:"00:33"},{day:"Fri",hour_from:"00:00",hour_to:"00:83"},{day:"Sat",hour_from:"02:00",hour_to:"05:33"},{day:"Thu",hour_from:"02:00",hour_to:"05:33"},{day:"Wed",hour_from:"12:00",hour_to:"14:00"},{day:"Sun",hour_from:"22:25",hour_to:"13:45"}],
      dedupe = src.reduce((res, item) =>
        (
          !res.find(({hour_from, hour_to}) =>
            hour_from == item.hour_from && hour_to == item.hour_to) ?
          res.push(item) :
          true, res
        ), [])

console.log(dedupe)

关于javascript - 通过2个匹配属性从对象数组中删除重复项，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/59881410/