c# - 在json.net中重命名JProperty

我有以下属性(property)

{
  "bad":
  {
    "Login": "someLogin",
    "Street": "someStreet",
    "House": "1",
    "Flat": "0",
    "LastIndication":
    [
      "230",
      "236"
    ],
    "CurrentIndication":
    [
      "263",
      "273"
    ],
    "Photo":
    [
      null,
      null
    ]
  }
}

以及如何将其从“坏”重命名为“好”。是的，我看到了Abi Bellamkonda的扩展方法

public static class NewtonsoftExtensions
{
    public static void Rename(this JToken token, string newName)
    {
        var parent = token.Parent;
        if (parent == null)
            throw new InvalidOperationException("The parent is missing.");
        var newToken = new JProperty(newName, token);
        parent.Replace(newToken);
    }
}

但它得到了这个证明

最佳答案

有点违反直觉的是，该扩展方法假定您要传递给它的token是JProperty的值，而不是JProperty本身。大概是为了使方括号语法易于使用:

JObject jo = JObject.Parse(json);
jo["bad"].Rename("good");

如果您引用了该属性，则可以在属性的Value上调用该扩展方法，如下所示:

JObject jo = JObject.Parse(json);
JProperty prop = jo.Property("bad");
prop.Value.Rename("good");

但是，这使代码看起来很困惑。最好改进扩展方法，使其在两种情况下都可以使用:

public static void Rename(this JToken token, string newName)
{
    if (token == null)
        throw new ArgumentNullException("token", "Cannot rename a null token");

    JProperty property;

    if (token.Type == JTokenType.Property)
    {
        if (token.Parent == null)
            throw new InvalidOperationException("Cannot rename a property with no parent");

        property = (JProperty)token;
    }
    else
    {
        if (token.Parent == null || token.Parent.Type != JTokenType.Property)
            throw new InvalidOperationException("This token's parent is not a JProperty; cannot rename");

        property = (JProperty)token.Parent;
    }

    // Note: to avoid triggering a clone of the existing property's value,
    // we need to save a reference to it and then null out property.Value
    // before adding the value to the new JProperty.
    // Thanks to @dbc for the suggestion.

    var existingValue = property.Value;
    property.Value = null;
    var newProperty = new JProperty(newName, existingValue);
    property.Replace(newProperty);
}

然后，您可以执行以下操作:

JObject jo = JObject.Parse(json);
jo.Property("bad").Rename("good");  // works with property reference
jo["good"].Rename("better");        // also works with square bracket syntax

fiddle :https://dotnetfiddle.net/RSIdfx