我正在构建一个日志应用程序,在其中创建一个FocusArea对象,然后包含30个日志条目对象。
所以我在我的数据模型中创建了一对多关系。
然后我实现了两个NSManagedObject类:
@目标区域(FocusArea)
类焦点区域:NSManagedObject{

@NSManaged var focusName: String
@NSManaged var focusStart: NSDate
@NSManaged var focusEnd: NSDate
@NSManaged var completeFlag: Bool
//@NSManaged var entries: NSSet

var entries: NSMutableOrderedSet {
    return self.mutableOrderedSetValueForKey("entries")
}

}
@objc(条目)
类条目:NSManagedObject{
 @NSManaged var entryJournal: String
 @NSManaged var entryDate: NSDate
 @NSManaged var completeFlag: Bool
 @NSManaged var entryStatus: Bool
 @NSManaged var focus: FocusArea

}
我可以毫无问题地添加FocusArea,但是当我尝试创建30个Entry对象并存储在FocusArea.entries中时,所有的东西都会崩溃。
向FocusArea对象添加多个条目对象的正确方法是什么?
我离这儿远吗?
@IBAction func saveFocusArea(sender: AnyObject) {

    if txtFocusName.text != nil {

        let appDel: AppDelegate = UIApplication.sharedApplication().delegate as! AppDelegate
        let context: NSManagedObjectContext = appDel.managedObjectContext!

        //create new focus area
        let entFocus = NSEntityDescription.entityForName("FocusArea", inManagedObjectContext: context)
        let newFocus = FocusArea(entity:entFocus!, insertIntoManagedObjectContext: context)

        newFocus.focusName = txtFocusName.text!
        newFocus.focusStart = NSDate()
        newFocus.focusEnd = NSDate().dateByAddingTimeInterval(60*60*24*30)
        newFocus.completeFlag = false

        //initialize 30 new entries into core data
        let entEntry = NSEntityDescription.entityForName("Entry", inManagedObjectContext: context)

        for var i = 0; i < 30; i++ {

            let newEntry = Entry(entity:entEntry!, insertIntoManagedObjectContext: context)

            let c = Double(i)
            newEntry.entryDate = NSDate().dateByAddingTimeInterval(60*60*24*c)
            newEntry.entryJournal = ""
            newEntry.entryStatus = false
            newEntry.completeFlag = false

            //THIS IS THE PROBLEM AREA
            newFocus.entries.append(newEntry)
        }
        do {
            try context.save()
        } catch {
            print("There's a problem!")
        }
    }
}

最佳答案

我想出来了。我要做的就是:
newEntry.focus=新焦点。
因此,与其设置父对象与子对象之间的关系,不如将其从子对象设置为父对象。

10-07 15:05