c - FD_SET从无效的内存地址读取？

**编辑：我找到了解决办法**
我有一个奇怪的问题，对于那些敢于阅读以下内容的人来说：
我正在做作业，需要使用UNIX管道在进程之间发送消息。
我使用这段代码的目的是在提供的文件描述符上选择（）。如果有什么东西可以在不阻塞的情况下阅读，我想退货。如果不是，我想返回NULL并继续而不阻塞。
下面是我的“getMessage”函数中的代码，其中fd是文件描述符：

message* getMessage(int fd){
    int messageAvailable = 0;
    struct timeval timeout;
    fd_set fd2;

    //If there's a message available, read it; if not, continue on without delay
    timeout.tv_sec = 0;
    timeout.tv_usec = 0;
    FD_ZERO(&fd2);
    FD_SET(fd,&fd2);
    messageAvailable = select(FD_SETSIZE,&fd2,NULL,NULL,&timeout);
    if(messageAvailable){
        int bytesRead = 0;
        message* m;
        m = malloc(sizeof(message));
        //Get the header
        bytesRead = read(fd,m,sizeof(message));
        //If we got the whole message
        if(bytesRead == sizeof(message)){
            return m;
        }else{
            //If a message wasn't generated, free the space we allocated for it
            free(m);
            return NULL;
        }
    }else{
        return NULL;
    }
}

这段代码在一个循环中，循环在程序运行期间一直持续，在同一点（成功传输一条消息后的下一个getMessage（）调用）它会segfaults。显然，FD_SET行正在从无效的内存位置读取数据。
如果不发布我的所有代码，有人能猜到在这个简单的宏中会发生什么导致segfault吗？
我在下面发布了相关的调试信息，其中33行对应于上面的FD_SET行：

==1330== Invalid read of size 1
==1330==    at 0x804E819: getMessage (messages.c:33)
==1330==    by 0x8049123: main (messageTest.c:110)
==1330==  Address 0xde88d627 is not stack'd, malloc'd or (recently) free'd
==1330==
==1330==
==1330== Process terminating with default action of signal 11 (SIGSEGV)
==1330==  Access not within mapped region at address 0xDE88D627
==1330==    at 0x804E819: getMessage (messages.c:33)
==1330==    by 0x8049123: main (messageTest.c:110)
==1330==  If you believe this happened as a result of a stack
==1330==  overflow in your program's main thread (unlikely but
==1330==  possible), you can try to increase the size of the
==1330==  main thread stack using the --main-stacksize= flag.
==1330==  The main thread stack size used in this run was 8388608.
==1330==
==1330== HEAP SUMMARY:
==1330==     in use at exit: 344 bytes in 10 blocks
==1330==   total heap usage: 25 allocs, 15 frees, 2,492 bytes allocated
==1330==
==1330== LEAK SUMMARY:
==1330==    definitely lost: 12 bytes in 1 blocks
==1330==    indirectly lost: 0 bytes in 0 blocks
==1330==      possibly lost: 0 bytes in 0 blocks
==1330==    still reachable: 332 bytes in 9 blocks
==1330==         suppressed: 0 bytes in 0 blocks
==1330== Rerun with --leak-check=full to see details of leaked memory
==1330==
==1330== For counts of detected and suppressed errors, rerun with: -v
==1330== ERROR SUMMARY: 2 errors from 2 contexts (suppressed: 11 from 6)
Segmentation fault

最佳答案

哎呀。。。在做了一些处理之后，我意外地将-1作为FD传递到了函数中（这解释了为什么每次运行时它都发生在同一点上）。
这个问题可能已经结束了；我认为除了我的单一用法之外，它没有多大用处。