c++ - 未初始化的局部变量

此代码可以编译并运行，但会给出我无法修复的Microsoft编译器错误

警告C4700:使用了未初始化的局部变量”。

我认为这是代码的最后一行

#include <iostream>
using namespace std;

const int DIM0 = 2, DIM1 = 3, DIM2 = 4, DIM3 = 5;

void TestDeclar();

int main(){
    TestDeclar();
    cout << "Done!\n";
    return 0;
}

void TestDeclar(){
    //24 - array of 5 floats
    float xa[DIM3], xb[DIM3], xc[DIM3], xd[DIM3], xe[DIM3], xf[DIM3];
    float xg[DIM3], xh[DIM3], xi[DIM3], xj[DIM3], xk[DIM3], xl[DIM3];
    float xm[DIM3], xn[DIM3], xo[DIM3], xp[DIM3], xq[DIM3], xr[DIM3];
    float xs[DIM3], xt[DIM3], xu[DIM3], xv[DIM3], xw[DIM3], xx[DIM3];

    //6  - array of 4 pointers to floats
    float *ya[DIM2] = {xa, xb, xc, xd}, *yb[DIM2] = {xe, xf, xg, xh};
    float *yc[DIM2] = {xi, xj, xk, xl}, *yd[DIM2] = {xm, xn, xo, xp};
    float *ye[DIM2] = {xq, xr, xs, xt}, *yf[DIM2] = {xu, xv, xw, xx};

    //2 - array of 3 pointers to pointers of floats
    float **za[DIM1] = {ya, yb, yc};
    float **zb[DIM1] = {yd, ye, yf};

    //array of 2 pointers to pointers to pointers of floats
    float ***ptr[DIM0] = {za, zb};
    cout << &***ptr[DIM0] << '\n';
}

最佳答案

您正在访问ptr4D的末尾。 DIM0是2，比上一个索引1大!

将最后几行更改为:

//array of 2 pointers to pointers to pointers of floats
float ***ptr4D[DIM0] = {za, zb};
cout << &***ptr4D[0] << '\n';