mysql - 如何使用下面的查询获取每一行的余额

我想得到每个借方和贷方的余额，然后计算每行的余额。。

SELECT SUM(IF(s.AMT>0 AND s.SLE_CODE=11,s.AMT,0)) AS DEBIT,
       SUM(IF(s.AMT<0 AND s.SLE_CODE=11,s.AMT,0)) * -1 AS CREDIT
FROM
  sldtl AS s
LEFT JOIN
  transtype
ON
  transtype.TransTypeID = s.TR_CODE
WHERE
  s.SL_BRCODE= 1 AND s.SL_CLIENTID= 267 AND s.SLC_CODE= 13 AND s.SLT_CODE= 15 AND
  s.REF_NO= s.REF_NO AND s.TR_DATE >= (SELECT s.TR_DATE FROM sldtl AS s ORDER BY s.TR_DATE DESC LIMIT 1)-INTERVAL 6 MONTH
GROUP BY
  s.TR_DATE DESC, s.TR_CODE, s.TR_CTLNO

需要的结果

 +-----------+--------------+---------------+
 |    DEBIT  |    CREDIT    |    BALANCE    |
 +-----------+--------------+---------------+
 |      0.00 |       700.00 |       -700.00 |
 |      0.00 |       700.00 |      -1400.00 |
 |    400.00 |         0.00 |      -1000.00 |
 |   2000.00 |       500.00 |        500.00 |
 +-----------+--------------+---------------+

最佳答案

让我们考虑一下问题的简化版本：
只包含debit和credit列的表。您需要计算balance列：
平衡：

 debit    credit
   0        700
   0        700
 400          0
2000        500


SELECT
debit,
credit,
@balance := @balance + debit - credit AS balance
FROM balancetable, (SELECT @balance := 0) var;

SQL FIDDLE DEMO
所以在你的情况下会是：

SELECT
t.DEBIT,
t.CREDIT,
@balance := @balance + t.DEBIT - t.CREDIT AS BALANCE
FROM
(
    SELECT SUM(IF(s.AMT>0 AND s.SLE_CODE=11,s.AMT,0)) AS DEBIT,
                 SUM(IF(s.AMT<0 AND s.SLE_CODE=11,s.AMT,0)) * -1 AS CREDIT
    FROM
        sldtl AS s
    LEFT JOIN
        transtype
    ON
        transtype.TransTypeID = s.TR_CODE
    WHERE
        s.SL_BRCODE= 1 AND s.SL_CLIENTID= 267 AND s.SLC_CODE= 13 AND s.SLT_CODE= 15 AND
        s.REF_NO= s.REF_NO AND s.TR_DATE >= (SELECT s.TR_DATE FROM sldtl AS s ORDER BY s.TR_DATE DESC LIMIT 1)-INTERVAL 6 MONTH
    GROUP BY
        s.TR_DATE DESC, s.TR_CODE, s.TR_CTLNO
) AS t , (SELECT @balance := 0) var;