我需要在FolderScan
中创建一个新的构造函数,该构造函数包含“ Checkers”列表。并且所有这些“ Checkers”始终为return true
(请写出仅返回true的新Chekers List。)
但是问题是我不知道该怎么做并且不分解程序的结构。
代码(FolderScan和每个Cheker):
class FolderScan implements Runnable {
FolderScan(String path, BlockingQueue<File> queue, CountDownLatch latch,
File endOfWorkFile) {
this.path = path;
this.queue = queue;
this.latch = latch;
this.endOfWorkFile = endOfWorkFile;
checkers = new ArrayList<Checker>(Arrays.asList(
new ExtentionChecking(), new ProbeContentTypeCheking(),
new EncodingChecking() ));
}
@Override
public void run() {
try {
findFiles(path);
queue.put(endOfWorkFile);
latch.countDown();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
private void findFiles(String path) {
try {
File root = new File(path);
File[] list = root.listFiles();
for (File currentFile : list) {
boolean checksPassed = true;
if (currentFile.isDirectory()) {
findFiles(currentFile.getAbsolutePath());
} else {
for (Checker currentChecker : checkers) {
if (!currentChecker.check(currentFile)) {
checksPassed = false;
break;
}
}
if (checksPassed) {
queue.put(currentFile);
}
}
}
} catch (InterruptedException e) {
e.printStackTrace();
}
private String path;
private BlockingQueue<File> queue;
private CountDownLatch latch;
private File endOfWorkFile;
private List<Checker> checkers;
}
class ExtentionChecking implements Checker {
@Override
public boolean check(File currentFile) {
fileName = currentFile.getName().toLowerCase();
Set<String> extensions = new HashSet<String>(Arrays.asList(".txt",
".pdf", ".doc", ".docx", ".html", ".htm", ".xml", ".djvu",
".djv", ".rar", ".rtf", ".tmp"));
if (extensions.contains(fileName.substring(fileName.lastIndexOf(".")))) {
return true;
}
return false;
}
private String fileName;
}
class EncodingChecking implements Checker {
@Override
public boolean check(File currentFile) {
return detectEncoding(currentFile);
}
public static boolean detectEncoding(File file) {
detector = new CharsetDetector();
// validate input
if (null == file) {
throw new IllegalArgumentException("input file can't be null");
}
if (file.isDirectory()) {
throw new IllegalArgumentException(
"input file refers to a directory");
}
// read input file
byte[] buffer;
try {
buffer = readUTFHeaderBytes(file);
} catch (IOException e) {
throw new IllegalArgumentException(
"Can't read input file, error = " + e.getLocalizedMessage());
}
if(detector.setText(buffer) != null){
return true;
}
return false;
}
private static byte[] readUTFHeaderBytes(File input) throws IOException {
// read data
FileInputStream fileInputStream = new FileInputStream(input);
try {
byte firstBytes[] = new byte[50];
int count = fileInputStream.read(firstBytes);
if (count < 5) {
throw new IOException("Poor file!");
}
return firstBytes;
} finally {
fileInputStream.close();
}
}
private static CharsetDetector detector;
}
class ProbeContentTypeCheking implements Checker {
@Override
public boolean check(File currentFile) {
String mimeType = null;
try {
Path path = Paths.get(currentFile.getAbsolutePath());
byte[] data = Files.readAllBytes(path);
MagicMatch match = Magic.getMagicMatch(data);
mimeType = match.getMimeType();
} catch (MagicParseException | MagicMatchNotFoundException
| MagicException | IOException e) {
e.printStackTrace();
}
if (null != mimeType) {
return true;
}
return false;
}
}
题:
如何重构此代码-在此之后可以使
newAllwaysPassesBlocker()
并使所有Checers返回true? 最佳答案
始终返回true的检查器将是
class UncriticalChecker implements Checker {
@Override
public boolean check(File currentFile) {
return true;
}
}
不过,将这样的检查器添加到检查器列表毫无意义。您最好将列表留空。
我不太清楚为什么应该在FolderScan的构造函数中构造检查器。将它们作为参数传递给构造函数似乎更自然。
FolderScan(String path, BlockingQueue<File> queue, CountDownLatch latch,
File endOfWorkFile, List<Checker> checkers) {
this.path = path;
this.queue = queue;
this.latch = latch;
this.endOfWorkFile = endOfWorkFile;
this.checkers = checkers;
}
然后,当您初始化FolderScan时,将其传递给检查程序
List<Checker> checkers = new ArrayList<Checker>(Arrays.asList(
new ExtentionChecking(), new ProbeContentTypeCheking(),
new EncodingChecking() ));
FolderScan folderScan =
new FolderScan(path, queue, latch, endOfWorkFile, checkers);
或者,如果您希望创建一个返回所有文件的FolderScan,则向其传递一个空列表。
FolderScan folderScan =
new FolderScan(path, queue, latch, endOfWorkFile, Collections.emptyList());
编辑:
我现在了解到您希望测试课程。然后,UncriticalChecker就有意义了。如果要使用始终显示“是”的检查器来测试代码,请将其传递给构造函数:
List<Checker> checkers = Collections.singletonList(new UncriticalChecker());
FolderScan folderScan =
new FolderScan(path, queue, latch, endOfWorkFile, checkers);