php - 如何在现有的foreach中为已连接的SQL表进行php循环

我目前正试图了解如何使用联接表中的SQL结果在现有循环中循环结果。

首先，这是我当前的代码：

<?php
include('OrderCore/connect-db.php');
$POIds = array();
if ($result = $mysqli->query("SELECT ProductionOrderID FROM ProductionOrder" ) ) {
    while ($row = $result->fetch_object()) {
        $POIds[] = $row->ProductionOrderID;
    }
}
foreach ( $POIds as $index => $OrderId ) {
    if ( $result = $mysqli->query("
    SELECT *
    FROM ProductionOrder AS p
    LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID )
    LEFT JOIN NotGood AS n ON ( p.ProductionOrderID = n.NGID )
    LEFT JOIN BatchOrder AS b ON ( p.ProductionOrderID = b.ProductionOrderID)
    LEFT JOIN Brand AS bd ON ( p.ProductionOrderID = bd.BrandID )
    LEFT JOIN CustomerOrder AS co ON ( p.ProductionOrderID = co.COID )
    LEFT JOIN Customer AS c ON ( p.ProductionOrderID = c.CustomerID )
    LEFT JOIN CustomerOrderStatus AS cos ON ( p.ProductionOrderID = cos.COStatusID )
    WHERE p.ProductionOrderID='$OrderId'") ) {
        while( $row = $result->fetch_object() ) {
            print "<h1>Order: $OrderId</h1>";
            print "<table class='table table-striped'>";
            print "<tr> <th>PO ID</th> <th>PO #</th> <th>Order Quantity</th> <th>Balance Left</th> <th>Production Date</th> <th>Production Order Status</th> <th>Not Good ID</th> </tr>";
            print "<td>" . $row->ProductionOrderID . "</td>";
            print "<td>" . $row->PONum . "</td>";
            print "<td>" . $row->OrderQTY . "</td>";
            print "<td>" . $row->BalLeftNum . "</td>";
            print "<td>" . $row->ProductionDate . "</td>";
            print "<td>" . $row->ProductionOrderStatusID . "</td>";
            print "<td>" . $row->NGID . "</td>";
            print "</tr>";
            print "</table>";
            //BatchOrder
            print "<table class='table table-striped'>";
            print "<tr> <th>Batch ID</th> <th>Brand Name</th> <th>Batch Quantity</th> <th>Availability Date</th> <th>Remaining Balance</th> <th>Production Order ID</th> </tr>";
            print "<td>" . $row->BatchID . "</td>";
            print "<td>" . $row->BrandID . "</td>";
            print "<td>" . $row->BatchQTY . "</td>";
            print "<td>" . $row->AvailDate . "</td>";
            print "<td>" . $row->RemainBal . "</td>";
            print "<td>" . $row->ProductionOrderID . "</td>";
            print "</tr>";
            print "</table>";
            //CustomerOrder
            print "<table class='table table-striped'>";
            print "<tr> <th>Customer ID</th> <th>Customer Name</th> <th>Invoice Quantity</th> <th>Invoice #</th> <th>Shipping Date</th> <th>Batch ID</th> <th>CO Status</th> </tr>";
            print "<td>" . $row->COID . "</td>";
            print "<td>" . $row->CustomerID . "</td>";
            print "<td>" . $row->InvoiceQTY . "</td>";
            print "<td>" . $row->InvoiceNum . "</td>";
            print "<td>" . $row->ShipDate . "</td>";
            print "<td>" . $row->BatchID . "</td>";
            print "<td>" . $row->COStatusID . "</td>";
            print "</tr>";
            print "</table>";
        }
    }
    else
    {
        print "No results to display!";
    }
}
$mysqli->close();
?>

该代码当前产生以下结果：https://i.imgur.com/y7uh6nk.png。
这几乎是正确的预期行为...每个ProductionOrderID应生成一个新表，该表包含2个子表：BatchOrder和CustomerOrder。但目前每个子表只显示1个结果。

因此需要澄清的是，用户可以创建任意数量的ProductionOrder（因此foreach遍历整个数组）。每个ProductionOrder可以包含：零个，一个或许多BatchOrder，每个BatchOrder可以包含：零个，一个或许多CustomerOrder。

当前问题：
根据上方的屏幕快照链接，它仅显示1个BatchOrder和每个CustomerOrder 1个ProductionOrder。我的示例数据包含ProductionOrderID=1的多个批处理订单，但未显示。

我不确定这个问题是否部分与PHP和SQL有关。我是这两种语言的新手，但我怀疑不正确。但是，这是唯一（当前）正确显示每个LEFT JOIN以及每个ProductionOrder和BO的方法...并不是全部。我也怀疑我需要在现有的while循环中执行另一个循环，但是由于当前的尝试均未成功，因此我不确定采用正确的方法。

详细资料
这是我的数据库SQL的副本，其中包含示例数据：https://pastebin.com/A3rt8kX4

还有我的ERD以显示预期的行为：https://i.imgur.com/idVR5ev.png

我们非常感谢您提供的不仅帮助解决当前问题的帮助，而且还帮助我了解了为什么会出错。



编辑：1
我已经修复了SELECT语句中加入的键，但是现在只能看到一个PO：

https://i.imgur.com/doRmS0c.png

SELECT *
FROM ProductionOrder AS p
INNER JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderID )
INNER JOIN NotGood AS n ON ( p.ProductionOrderID = n.ProductionOrderID )
INNER JOIN BatchOrder AS b ON ( p.ProductionOrderID = b.ProductionOrderID )
INNER JOIN Brand AS bd ON ( b.BatchID = bd.BatchID )
INNER JOIN CustomerOrder AS co ON ( b.BatchID = co.BatchID )
INNER JOIN Customer AS c ON ( co.COID = c.COID )
INNER JOIN CustomerOrderStatus AS cos ON ( co.COID = cos.COID )
WHERE p.ProductionOrderID='$OrderId'") ) {

最佳答案

您需要将主键连接到相应的外键，例如：

LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID )

应该

LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderID )

大多数联接都存在相同的问题。