python - 如何在osmnx上基于一些“手动选择”的节点绘制路径？

我想在osmnx地图上绘制路线。当我尝试手动创建路线时，它不起作用。

import networkx as nx
import osmnx as ox
import requests
import matplotlib.cm as cm
import matplotlib.colors as colors
location_point = (50.345559621674596, 7.576892382877531)
G = ox.graph_from_point(location_point, distance=500,
distance_type='network', network_type='walk')
origin_node = ox.get_nearest_node(G, location_point)
destination_node = list(G.nodes())[-1]
fig, ax = ox.plot_graph(G)
G=nx.convert_node_labels_to_integers(G)
route = [3 ,1 ,41 ,40 ,98 ,62 ,67 ,107 ,94 ,83 ,39 ]
ox.plot_route_folium(G,route)

我希望地图上有彩色的路线，但我却收到此错误。

    ---------------------------------------------------------------------------
    IndexError                                Traceback (most recent call last)
    <ipython-input-9-11235dc07ef4> in <module>()
    ----> 1 ox.plot_route_folium(G,route)

    ~\Anaconda3\lib\site-packages\osmnx\plot.py in plot_route_folium(G, route, route_map, popup_attribute, tiles, zoom, fit_bounds, route_color, route_width, route_opacity)
        907     gdf_edges = graph_to_gdfs(G, nodes=False, fill_edge_geometry=True)
        908     route_nodes = list(zip(route[:-1], route[1:]))
    --> 909     index = [gdf_edges[(gdf_edges['u']==u) & (gdf_edges['v']==v)].index[0] for u, v in route_nodes]
        910     gdf_route_edges = gdf_edges.loc[index]
        911

    ~\Anaconda3\lib\site-packages\osmnx\plot.py in <listcomp>(.0)
        907     gdf_edges = graph_to_gdfs(G, nodes=False, fill_edge_geometry=True)
        908     route_nodes = list(zip(route[:-1], route[1:]))
    --> 909     index = [gdf_edges[(gdf_edges['u']==u) & (gdf_edges['v']==v)].index[0] for u, v in route_nodes]
        910     gdf_route_edges = gdf_edges.loc[index]
        911

    ~\Anaconda3\lib\site-packages\pandas\core\indexes\base.py in __getitem__(self, key)
       2082
       2083         if is_scalar(key):
    -> 2084             return getitem(key)
       2085
       2086         if isinstance(key, slice):

    IndexError: index 0 is out of bounds for axis 0 with size 0

如果我尝试通过最短路径算法查找路线并将其可视化在地图上，则效果很好。但我想画出这条特定的路线

最佳答案

OSMnx使用节点的OSMID。运行G=nx.convert_node_labels_to_integers(G)时，将覆盖这些OSMID。但是，您也没有在图形边缘的u和v属性中覆盖它们，这些属性标识边缘的端点（使用OSMID）。