python - 检查对象是否为字符串列表？

检查对象是否是字符串列表而不是嵌套循环的优雅方法是什么？可能这里必须有构造结构化迭代的常规方法。
升级版
像这样的：

l = [['a', 'b', 'c'], ['d', 1], 3, ['e', 2, 'f']]

def recurse(iterable, levels):
    results = []
    try:
        fn = levels[0]
    except IndexError:
        return
    for e in iterable:
        results.append(fn(e))
        try:
            results.extend(recurse(e, levels[1:]))
        except TypeError:
            pass
    return results

instance_of = lambda t: lambda e: isinstance(e, t)
print(recurse(l, [instance_of(list), instance_of(basestring)]))

升级版#2
我做了一些自制的函数式编程，现在它检查字符串列表：

from collections import Iterable
from itertools import imap, chain


def compose(f, g):
    return lambda *a, **kw: f(g(*a, **kw))

def concat(iterable):
    return chain.from_iterable(iterable)

def mk_iter(o):
    if isinstance(o, Iterable):
        return o
    else:
        return [o]

def put_in(f, g):
    """To support spirit of the Olympics :)"""
    return lambda e: concat(
        [mk_iter(f(e)),
         concat(imap(compose(mk_iter, g), mk_iter(e)))]
    )


ckr = lambda t: lambda e: isinstance(e, t)

l = [[['a', 'b'], ['c']], [['d'], ['1']], [1]]

fns = [ckr(list), ckr(list),ckr(list), ckr(str)]
fns.reverse()

print(list(reduce(lambda x, y: put_in(y, x), fns)(l)))

最佳答案

lol = [["a", "b"], ["c"], ["d", "e"], [1]]

from itertools import chain
print isinstance(lol, list) and all(isinstance(items, list) \
        and all(isinstance(item, str) for item in items) for items in lol)

关于python - 检查对象是否为字符串列表？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/21723910/