java - 精细记录时将文件拆分为块(java 8)

找到一段开始记录时，我有一段代码将文件“分成”几块。

List<StringBuilder> list = new ArrayList<>();
StringBuilder jc = null;
try (BufferedReader br = Files.newBufferedReader(Paths.get("")) {
    for (String line = br.readLine(); line != null; line = br.readLine()) {
        if (line.startsWith("REQ00")) {
            jc = new StringBuilder();
            list.add(jc);
        }
        jc.append(line);
    }
} catch (IOException e) {
    e.printStackTrace();
}

有什么办法可以将此代码“转换”为Java 8 Stream方法吗？

最佳答案

使用正确的工具完成工作。使用Scanner，就像

List<String> list = new ArrayList<>();
try(Scanner s = new Scanner(Paths.get(path))) {
    s.useDelimiter(Pattern.compile("^(?=REQ00)", Pattern.MULTILINE));
    while(s.hasNext()) list.add(s.next());
} catch (IOException e) {
    e.printStackTrace();
}

现在，您的代码具有创建StringBuilder且不保留换行符的特殊要求。因此，扩展版本为：

List<StringBuilder> list = new ArrayList<>();
try(Scanner s = new Scanner(Paths.get(path))) {
    s.useDelimiter(Pattern.compile("^(?=REQ00)", Pattern.MULTILINE));
    while(s.hasNext()) list.add(new StringBuilder(s.next().replaceAll("\\R", "")));
} catch (IOException e) {
    e.printStackTrace();
}

一个更有效的变体是

List<StringBuilder> list = new ArrayList<>();
try(Scanner s = new Scanner(Paths.get(path))) {
    s.useDelimiter(Pattern.compile("^(?=REQ00)", Pattern.MULTILINE));
    while(s.hasNext()) list.add(toStringBuilderWithoutLinebreaks(s.next()));
} catch (IOException e) {
    e.printStackTrace();
}

…

static final Pattern LINE_BREAK = Pattern.compile("\\R");
static StringBuilder toStringBuilderWithoutLinebreaks(String s) {
    Matcher m = LINE_BREAK.matcher(s);
    if(!m.find()) return new StringBuilder(s);
    StringBuilder sb = new StringBuilder(s.length());
    int last = 0;
    do { sb.append(s, last, m.start()); last = m.end(); } while(m.find());
    return sb.append(s, last, s.length());
}

从Java 9开始，您还可以对其使用Stream操作：

List<StringBuilder> list;
try(Scanner s = new Scanner(Paths.get(path))) {
    list = s.useDelimiter(Pattern.compile("^(?=REQ00)", Pattern.MULTILINE))
            .tokens()
            .map(string -> toStringBuilderWithoutLinebreaks(string))
            .collect(Collectors.toList());
} catch (IOException e) {
    e.printStackTrace();
    list = List.of();
}