我试图使用昂首阔步的偏转器来建立服务。
但是当我试图将复杂的对象发布到我的摇摇欲坠的控制器时,currenltl我遇到了一些问题。请看下面我提供的配置。
我的swagger.yaml:
swagger: "2.0"
info:
version: 1.0.0
title: Dummy Controller
basePath: /v1
tags:
- name: Dummy Controller
description: Dummy controller
schemes:
- http
paths:
/someService/create:
post:
tags:
- someService
summary: Test
description: ""
operationId: createPoint
consumes:
- application/json
- application/xml
produces:
- application/xml
- application/json
parameters:
- in: body
name: body
description: Created object
required: false
schema:
$ref: '#/definitions/Point'
responses:
default:
description: successful operation
definitions:
Point:
title: Point
description: ''
type: object
properties:
latitude:
description: ''
type: string
longitude:
description: ''
type: string
required:
- latitude
- longitude
ApiResponse:
properties:
code:
type: integer
format: int32
type:
type: string
message:
type: string
xml:
name: "##default"
我的控制器:
public class SomeServiceController {
public ResponseContext createPoint(RequestContext request, Point point){
System.out.println(point);
return new ResponseContext()
.status(Status.OK);
}
}
当我试图发布这样的帖子时:
POST http://localhost:8080/v1/someService/create
{
"latitude":"10",
"longitude":"20"
}
我越来越
11:36:51.814 [qtp931940545-13] ERROR i.s.i.c.SwaggerOperationController - failed to invoke method public io.swagger.inflector.models.ResponseContext com.swagger.test.SomeServiceController.createPoint(io.swagger.inflector.models.RequestContext,com.swagger.test.model.Point)
java.lang.IllegalArgumentException: argument type mismatch
我的依赖:
<dependencies>
<dependency>
<groupId>io.swagger</groupId>
<artifactId>swagger-inflector</artifactId>
<version>1.0.2</version>
</dependency>
<dependency>
<groupId>org.apache.cxf</groupId>
<artifactId>cxf-rt-frontend-jaxrs</artifactId>
<version>3.1.1</version>
</dependency>
</dependencies>
请帮忙!我错过了什么?
最佳答案
发现下一个问题:
我的模型对象(点)放置在错误的包装中。
如果变形器找不到模型,它将通过JsonNode传递给Controller方法。
那就是为什么我收到参数类型不匹配的原因。 Java无法将JsonNode映射到Point。
希望对别人有帮助!