c - C中偶数和奇数位的数字总和

我需要在整数的偶数和奇数位添加数字。说，让数字=1234567。偶数位的总和= 2 + 4 + 6 = 12奇数位的总和= 1 + 3 + 5 + 7 = 16

我目前拥有的代码是：

int returnsum(int num) {
    while(num) {
        rem=num%10;
        sum=sum+rem;
        num=num/10);
    }
    while(sum) {
        a=sum%10;
        arr[i]=a:
        sum=sum/10; i++;
    }
    for(i=0;a[i];i+=2) {
        summ=summ+a[i];
    }
    return summ;
}

void main()
{
  int n,m,oddSum=0,evenSum=0;
  printf("Please insert the number for the program:");
  scanf("%d",&n);
  while (n!=0) {
   oddSum += n % 10;
   n /= 10;
   evenSum += n % 10;
   n /=10;
  }
 printf("Sum of digits in even  places:%d\n",evenSum);
 printf("Sum of digits in odd  places:%d\n",oddSum);
}

最佳答案

这是您的问题的解决方案：

void main()
{
 int n,m,oddSum=0,evenSum=0;
 printf("Please insert the number for the program:");
 scanf("%d",&n);
 int flag=0;
 int counter=1;
 while (n!=0) {
   if(counter%2==0)
   {
     evenSum += n % 10;
     n /= 10;
   }
   else
   {
     oddSum += n % 10;
     n /= 10;
   }
   counter++;
 }

 if(counter%2==0)
 {
   int temp=oddSum;
   oddSum=evenSum;
   evenSum=temp;
 }
 printf("Sum of digits in even  places:%d\n",evenSum);
 printf("Sum of digits in odd  places:%d\n",oddSum);
}

关于c - C中偶数和奇数位的数字总和，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/27836116/