表:

laterecords
-----------
studentid - varchar
latetime - datetime
reason - varchar

我的问题:
SELECT laterecords.studentid,
laterecords.latetime,
laterecords.reason,
( SELECT Count(laterecords.studentid) FROM laterecords
      GROUP BY laterecords.studentid ) AS late_count
FROM laterecords

我得到“mysql子查询返回多行”错误。
我知道此查询使用以下查询的解决方法:
SELECT laterecords.studentid,
laterecords.latetime,
laterecords.reason
FROM laterecords

然后使用php循环查看结果并执行以下查询以获取late_count并将其回声输出:
SELECT Count(laterecords.studentid) AS late_count FROM laterecords

但我想也许有更好的解决办法?

最佳答案

简单的解决方法是在子查询中添加一个WHERE子句:

SELECT
    studentid,
    latetime,
    reason,
    (SELECT COUNT(*)
     FROM laterecords AS B
     WHERE A.studentid = B.student.id) AS late_count
FROM laterecords AS A

更好的选择(就性能而言)是使用连接:
SELECT
    A.studentid,
    A.latetime,
    A.reason,
    B.total
FROM laterecords AS A
JOIN
(
    SELECT studentid, COUNT(*) AS total
    FROM laterecords
    GROUP BY studentid
) AS B
ON A.studentid = B.studentid

10-06 13:44