我正在尝试在本地OSX 10.11中启动QLocalServer。

我有客户端尝试循环连接到服务器:

int connect(const char* filename) {
  int sock;
  struct sockaddr_un serv_addr;

  memset(&serv_addr, 0x00, sizeof(serv_addr));
  serv_addr.sun_family = AF_LOCAL;
  strncpy(serv_addr.sun_path, filename, sizeof(serv_addr.sun_path) - 1);

  if ((sock = socket(AF_UNIX, SOCK_STREAM, 0)) == -1) {
    return sock;
  }

  if (connect(sock, (struct sockaddr *)&serv_addr, sizeof(serv_addr)) == -1) {
    close(sock);
    sock = -1;
    return sock;
  }

  return sock;
}

int main() {
  int sock;
  while((sock = connect("my_socket_server")) == -1) {
    usleep(3000);
  }

  // The code never reaches this line

  const char* buffer = "hello";
  if (send(sock, buffer, strlen(buffer), 0) < 0) {
    exit(1);
  }

  return 0;
}


当此代码运行时,我尝试在另一个应用程序中启动QLocalServer:

// Starting server:

QString socket_path = "my_socket_server";
QLocalServer::removeServer(socket_path);
if (!server.listen(socket_path)) {
  return false;
}

connect(&server, &QLocalServer::newConnection, this, &MyServerClass::newConnection);

...

void MyServerClass::newConnection() {
  socket = server.nextPendingConnection(); // socket - member of MyServerClass
  connect(socket, &QLocalSocket::disconnected, socket, &QLocalSocket::deleteLater);
  connect(socket, &QLocalSocket::readyRead, this, &MyServerClass::readyRead);
}

...

void MyServerClass::readyRead() {
  if (!socket->bytesAvailable()) {
    exit(1); // THIS CODE WAS CALLED. WHY?
  }

  ...
}


为什么在调用readyRead时字节不可用?

最佳答案

您可能会获得多个连接,在这种情况下,socket变量可能指向与发出readyRead信号的对象不同的对象。使用QObject::sender在插槽中获取正确的对象,或者使用QSignalMapper。如果您使用的是Qt5,则还可以使用lambda函数并捕获socket对象。

10-06 11:25