编译器抱怨一个未知的标识符,似乎它不能识别我的多个声明中的任何一个,我在哪里错?

if attached {INTEGER_REF} field.item as l_int
        or attached {INTEGER_64} field.item as l_int
        or ( attached {TUPLE} field.item as l_tuple and then attached {INTEGER_64} l_tuple.item (1) as l_int ) then
    Result.put_integer (l_int.to_integer_64, primary_key_db_column_name)
elseif attached {STRING} field.item as l_s then
    Result.put_string (l_s, primary_key_db_column_name)
end

compiler-errors -  Eiffel : local declaration in or and and failed to compile-LMLPHP

更新资料

因为这似乎是一个有效的表达式,所以我认为,如果在的每个分支中都声明了l_int,则应该可以在然后范围内使用它。

但是似乎表达式是有效的
if attached a.b as l_b and then attached l_b.c as l_c then
    l_c.is_available_in_this_scope
    l_b.is_available_in_this_scope
else
    io.putstring ("you are wrong dear and either l_b and l_c are not available!")
end

虽然这个不行!
if attached a.b as l_b and then attached l_b.c as l_c
        or attached a.x as l_b and then attached l_x.d as l_c then
    l_c.is_available_in_this_scope -- Compiler complain about l_c
    l_b.is_available_in_this_scope -- Compiler complain about l_b
else
    io.putstring ("you are wrong dear and either l_b and l_c are not available!")
end

用我的代码

编译
    if attached {INTEGER_REF} field.item as l_int then
        Result.put_integer (l_int.to_integer_64, primary_key_db_column_name)
    elseif attached {INTEGER_64} field.item as l_int then
        Result.put_integer (l_int, primary_key_db_column_name)
    elseif attached {TUPLE} field.item as l_tuple and then attached {INTEGER_64} l_tuple.item (1) as l_int then
        Result.put_integer (l_int, primary_key_db_column_name)
    elseif attached {STRING} field.item as l_s then
        Result.put_string (l_s, primary_key_db_column_name)
    else
        logger.write_error ("to_json-> Type not found in matching:" + field.item.out)
        check
            not_found_item_type: False
        end
    end

虽然这个不是
if attached {INTEGER_REF} field.item as l_int then
    Result.put_integer (l_int.to_integer_64, primary_key_db_column_name)
elseif attached {INTEGER_64} field.item as l_int
        or attached {TUPLE} field.item as l_tuple and then attached {INTEGER_64} l_tuple.item (1) as l_int then
    Result.put_integer (l_int, primary_key_db_column_name) -- Unknown identifier `l_int`
elseif attached {STRING} field.item as l_s then
    Result.put_string (l_s, primary_key_db_column_name)
else
    logger.write_error ("to_json-> Type not found in matching:" + field.item.out)
    check
        not_found_item_type: False
    end
end

最佳答案

对象测试具有范围。用OT表示对象测试,其范围为

if OT         then A else B end
if OT and ... then A else B end
if OT or  ... then C else B end

只是A。因此,对于析取而言,作用域为空,并且您不能在任何分支中使用对应的局部对象测试。

如果条件中有两个对象测试,则它们的范围可能重叠或不重叠:
if OT1 and      OT2 then A else B end
if OT1 and then OT2 then A else B end
if OT1 or       OT2 then C else B end

在这里,像以前一样,OT1的对象测试局部变量具有范围A。另外,对于and then,作用域包括OT2,特别是OT2可以使用OT1的本地变量。出于相同的原因,OT2不能使用OT1的同一对象测试本地。

对于析取,OT1OT2的对象测试局部变量的范围为空。为了提供更多信息,带有助记符名称的相同代码如下所示:
if attached e1 as x and      attached e2_without_x as y then use_x_and_y else B end
if attached e1 as x and then attached e2_with_x    as y then use_x_and_y else B end
if attached e1 as x or       attached e2_without_x as y then no_x_no_y   else B end

如果所有涉及的表达式的类型都是相同的(不是这种情况,因为类型为INTEGER_64INTEGER_REF),仍然可以仅用一个第一分支重写示例:
if attached
       if attached {INTEGER_64_REF} field.item as i then
           i
       elseif
           attached {TUPLE} field.item as t and then
           t.count > 0 and then
           attached {INTEGER_64_REF} t.item (1) as i
       then
           i
       else
           Void
       end
   as j
then
   -- Use j
...

但这变得太麻烦了,使用多个分支或临时局部变量似乎是一个更好的选择。

10-06 10:31