javascript - 生成脚本以每隔n秒检查一次鼠标是否移动

我想创建一个JavaScript函数，每隔n秒调用一次self
因此，如果在移动鼠标时调用此函数，请勿发出ajax请求，否则：进行ajax调用
理论：

function CheckIfMouseIsMoving(){
if(!MouseMoving){
// Make ajax call
}
else{return false;}
}

setInterval(CheckIfMouseIsMoving,3000);

最佳答案

您可以使用setTimeout()和document.onmousemove

let MouseMoving = false;
let tm;
document.onmousemove = function(e){
  MouseMoving = true;
  if(tm) clearTimeout(tm)
  tm = setTimeout(() => MouseMoving = false,1000);
}


function CheckIfMouseIsMoving(){
  if(!MouseMoving){
    console.log("Mousse was not moving")
  }
  else{
    console.log("Mousse was moving")
    return false;
  }
}

setInterval(CheckIfMouseIsMoving,3000)