c++ - 在空格上选择性地分割字符串

我的命令是:

move 1 "South Africa" "Europe"

码:

do
{
  cut = text.find(' ');
  if (cut == string::npos)
  {
    params.push_back(text);
  }
  else
  {
    params.push_back(text.substr(0, cut));
    text = text.substr(cut + 1);
  }
}
while (cut != string::npos);

问题是South Africa被分为South和Africa，我需要它来保留South Africa。

裁切后的参数:

1, South, Africa, Europe

我需要它是:

1, South Africa, Europe

我怎样才能做到这一点？用正则表达式？

命令的另一个示例:

move 3 "New Island" "South Afrika"

并且我的代码在''之后切掉，我需要在参数中往回推

3, New Island, South Africa

我的代码使:

3,"New,Island","South,Africa"

最佳答案

您可以使用std::stringstream和std::getline解析字符串

#include <iostream>
#include <sstream>
#include <string>

int main() {
    std::string text("move 3 \"New Island\" \"South Afrika\"");
    std::string command, count, country1, country2, temp;
    std::stringstream ss(text);

    ss >> command >> count;
    ss.str("");
    ss << text;
    std::getline(ss, temp, '\"');
    std::getline(ss, country1, '\"');
    std::getline(ss, temp, '\"');
    std::getline(ss, country2, '\"');

    std::cout << command << ", " << count << ", " <<
        country1 << ", " << country2 << std::endl;
    return 0;
}

关于c++ - 在空格上选择性地分割字符串，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/17177361/