我想从以下InputStream获取“ SearchResult”值:

HTTP/1.1 200 OK
Content-Type: application/soap+xml; charset=utf-8
Content-Length: length

<?xml version="1.0" encoding="utf-8"?>
<soap12:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap12="http://www.w3.org/2003/05/soap-envelope">
    <soap12:Body>
        <SearchResponse xmlns="[url here]">
            <SearchResult>[THIS VALUE HERE]</SearchResult>
        </SearchResponse>
      </soap12:Body>
</soap12:Envelope>


我一直在尝试使用DOM解析器,但是遇到了麻烦,并且不确定是否是正确的方法:

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder db;
Document doc = null;

db = factory.newDocumentBuilder();
InputSource inStream = new InputSource();
inStream.setCharacterStream(new StringReader(soapResponse));
doc = db.parse(inStream);

NodeList nl = doc.getElementsByTagName("SearchResult");
//Not sure how to get the value... Everything I've tried returned "null". Help?


我怎样才能做到这一点?

最佳答案

对于Java和Android 8级或更高版本:
nodeList.item(0).getTextContent()

对于Android 1级及更高版本:
nodeList.item(0).getFirstChild().getNodeValue()

10-06 06:19