我正在使用下一个代码在label中显示图像,在picture列为空时不设置标签:
ResultSet rset2 = stmnt.executeQuery("select Picture from Pictures where Client_ID_pass =1" );
while(rset2.next()){
byte[] Passimg = rset2.getBytes("Picture");
//Resize The ImageIcon
ImageIcon Passimage = new ImageIcon(Passimg);
Image Passim = Passimage.getImage();
Image PassmyImg = Passim.getScaledInstance(PassLBL.getWidth(), PassLBL.getHeight(),Image.SCALE_SMOOTH);
ImageIcon newPassImage = new ImageIcon(PassmyImg);
PassLBL.setIcon(newPassImage);
if(Passimg.length < 0){
PassLBL.settext("No Picture");
PassLBL.setIcon(null);
}
}
我试过下一个:
if(Passimg.equals(空)
{PassLBL.settext(“没有图片”);}
试过了
如果(Passimg==null)
{PassLBL.settext(“没有图片”);}
但没用! 最佳答案
从结果集中检索数据时
byte[] Passimg = rset2.getBytes("Picture");
把if语句放在那里
if(passimg == null) {
label.setText("nothing")
lable.setIcon(null);//to remove the old picture
}else {
//show the image like you did before
lable.setText("");
icon=create your icon here
lable.setIcon(icon);
}
我不明白你到底需要什么希望这能帮到你