为什么getTime()出错?我已经尝试了一切,但无法弄清楚问题出在哪里。据我所知,我已经将String arrayOpportunity [2]转换为日期。 (它最初是一个String。)谢谢!
SimpleDateFormat df = new SimpleDateFormat();
df.applyPattern("yyyy-MM-dd HH:mm:ss");
// Calendar timestamp = Calendar.getInstance();
// timestamp.setTime(df.parse(arrayOpportunity2)[0]);
arraySuspects.add(arrayGPS[0]);
// }
// long timediff = coord2.getTimestamp().getTimeInMillis() -
// coord1.getTimestamp().getTimeInMilis();
Date convertedDate = df.parse(arrayOpportunity[2]);
Date duration = df.parse("0000-00-00 00:14:59");
Date lastTime = df.parse(arrayOpportunity[2]);
// SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy/mm/dd");
System.out.println(arrayOpportunity[2]);
// arrayOpportunity[2].setTime(arrayOpportunity[2].getTime() + duration);
// lastTime += duration;
arrayOpportunity[2].setTime(arrayOpportunity[2].getTime() + (((14 * 60) + 59)* 1000));
最佳答案
调用df.parse(arrayOpportunity[2]);
不会将arrayOpportunity[2]
转换为Date
,而是将该值分配给lastTime
。在您的代码调用lastTime.getTime()
而不是arrayOpportunity[2].getTime()
中,因为arrayOpportunity[2]
仍然是String
// Create your date parser
SimpleDateFormat df = new SimpleDateFormat();
// Set the date pattern
df.applyPattern("yyyy-MM-dd HH:mm:ss");
// Create a Date object by parsing the value of arrayOpportunity[2]
Date lastTime = df.parse(arrayOpportunity[2]);
// Set a new value to the Date object by performing a calculation on the result of getTime()
lastTime.setTime(lastTime.getTime() + (((14 * 60) + 59)* 1000));