我正在尝试自动生成文档以供阅读文档。我将一些依赖项模拟为they suggest in FAQ,但从函数的类型注释可以看出文档的某些部分看起来像
返回类型:
这当然是不能接受的。所以我重写了mock如下:
from unittest.mock import Mock
class ModuleMock(Mock):
def __init__(self, path='', *args, **kwargs):
super().__init__(*args, *kwargs)
self.path = path
def __getattr__(self, name):
return ModuleMock(path=self.path + '.' + name)
def __repr__(self):
return self.path
所以我可以
>>> x = ModuleMock('x')
>>> x
x
>>> x.y.z
x.y.z
但有了这个我就例外了
...
File "<frozen importlib._bootstrap>", line 906, in _find_spec
File "<frozen importlib._bootstrap_external>", line 1280, in find_spec
File "<frozen importlib._bootstrap_external>", line 1246, in _get_spec
TypeError: 'ModuleMock' object is not iterable
当我试图从
MagicMock
继承时,我得到RecursionError
。如何正确地隔离文档生成的依赖项,并使文档可读?
最佳答案
这是因为MagicMock使用_mock_methods
和_mock_unsafe
属性,而Mock不使用(似乎)。
我使用Python2.7
正确实施:
from mock import MagicMock
class ModuleMock(MagicMock):
def __init__(self, path='', *args, **kwargs):
super(ModuleMock, self).__init__(*args, **kwargs)
self.path = path
def __repr__(self):
return self.path
def __getattr__(self, name):
#print(name)
if name in ('_mock_methods', '_mock_unsafe'):
return super(ModuleMock, self).__getattr__(name)
return ModuleMock(self.path + "." + name)
if __name__ == '__main__':
x = ModuleMock('x')
print(x)
print(x.y.z)
因此,如果在
__getattr__
中打印属性名,可以看到MagicMock有几个调用。结果:
_mock_methods
_mock_methods
x
y
_mock_methods
z
_mock_methods
_mock_methods
x.y.z
关于python - 如何重新定义MagicMock __str__方法?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/54021062/