我有一个字符串数组
{"ted", "williams", "golden", "voice", "radio"}
我希望这些关键字的所有可能组合都采用以下形式:
{"ted",
"williams",
"golden",
"voice",
"radio",
"ted williams",
"ted golden",
"ted voice",
"ted radio",
"williams golden",
"williams voice",
"williams radio",
"golden voice",
"golden radio",
"voice radio",
"ted williams golden",
"ted williams voice",
"ted williams radio",
.... }
我已经去了好几个小时了,没有任何有效的结果(高级编程的副作用?)。
我知道解决方案应该很明显,但是老实说,我被卡住了!接受Java/C#解决方案。
编辑:
编辑2 :查看答案中的链接后,事实证明 Guava 用户可以在com.google.common.collect.Sets中使用powerset方法
最佳答案
编辑:正如FearUs指出的那样,更好的解决方案是使用Guava的Sets.powerset(Set set)。
编辑2:更新了链接。
this solution的快速翻译:
public static void main(String[] args) {
List<List<String>> powerSet = new LinkedList<List<String>>();
for (int i = 1; i <= args.length; i++)
powerSet.addAll(combination(Arrays.asList(args), i));
System.out.println(powerSet);
}
public static <T> List<List<T>> combination(List<T> values, int size) {
if (0 == size) {
return Collections.singletonList(Collections.<T> emptyList());
}
if (values.isEmpty()) {
return Collections.emptyList();
}
List<List<T>> combination = new LinkedList<List<T>>();
T actual = values.iterator().next();
List<T> subSet = new LinkedList<T>(values);
subSet.remove(actual);
List<List<T>> subSetCombination = combination(subSet, size - 1);
for (List<T> set : subSetCombination) {
List<T> newSet = new LinkedList<T>(set);
newSet.add(0, actual);
combination.add(newSet);
}
combination.addAll(combination(subSet, size));
return combination;
}
测试:
$ java PowerSet ted williams golden
[[ted], [williams], [golden], [ted, williams], [ted, golden], [williams, golden], [ted, williams, golden]]
$