我在使用链表操作某些内容时遇到了困难,

问题的第一件事就是代码的这一部分,我从文件中读取数据,并用它填充节点。但是我在代码中指示的地方不断收到警告,分别将指针类型int与int和不兼容的指针类型进行比较:

void readfile(node *curr, node *newlist, int *quanta, int *readincrement, int *newincrement, int *procnumb)
{
    int i;
    FILE *myFile;
    myFile = fopen("data.txt", "r");
    fscanf(myFile,"%d",quanta);
    fscanf(myFile,"%d",newincrement);
    fscanf(myFile,"%d",readincrement);
    fscanf(myFile,"%d",procnumb);

    newlist = malloc(sizeof(node));
    curr = newlist;
    for(i=0;i<procnumb;i++)//pointer error
    {
        curr->process = 'A' + i;
        printf("%s",curr->process);
        curr->state = '-';
        printf("%s",curr->state);
        fscanf(myFile,"%d",&curr->NUT);
        printf("%d",curr->NUT);
        fscanf(myFile,"%d",&curr->AT);
        printf("%d", curr->AT);
        curr->Prio = '0';
        printf("%d",curr->Prio);
        curr->next = malloc(sizeof (node));
        curr->next = curr;//pointer error.
    }
}

第二个问题是具有将节点从newlist的顶部移到readylist的底部的功能,我在代码中指示的位置不断收到错误,我也不知道为什么:
//move node from new list, to ready list.
void move(node *newlist, node *readylist)
{
    readylist->next = malloc(sizeof(node));
    while(readylist->next != NULL)
    {
        if(readylist->next == newlist)
            readylist->next = readylist->next->next;//pointer error here.
        readylist = readylist->next;
    }

    readylist->next = newlist;
    newlist->next = NULL;
    return readylist;
}

在您的回答中,我希望能简要解释它们为什么会发生,目前我确实在努力解决这个问题,并努力解决这个问题。

编辑:忘记在这里添加结构部分:
struct record//too contain several data types.
{
    char process;
    char state;
    int  NUT;
    int  AT;
    int  Prio;

    struct reord *next;
};
typedef struct record node;

void move(node *newlist, node *readylist);

void readfile(node *reading,node *newlist, int *quanta, int *readincrement, int *newincrement, int *procnumb);

main()
{
    int quanta, readincrement, newincrement, procnumb;
    node *readylist = {NULL};//pointing at nothing.
    node *newlist = {NULL};
    node *curr = {NULL};
    node *next = {NULL};
    node *Rcurr = {NULL};
    node *Rnext = {NULL};
}

最佳答案

对于问题1:

更换
for(i=0;i<procnumb;i++) \这里您正在比较一个整数和一个指向整数的地址


for(i=0;i<*procnumb;i++) \现在您正在比较一个整数和一个整数

关于c - 链接列表,操作困难,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/28629227/

10-12 03:33