java - 自定义Spring Bean参数

我正在使用发布在激活器上的Spring Akka示例来创建Spring托管的bean actor。这是我当前正在使用的代码，其中包括一个演示类:

@Component
class Test extends UntypedActor {

    @Autowired
    protected ObjectMapper objectMapper;

    protected final Account account;
    protected final Order order;

    public Test(Account account, Order order) {
        this.account = account;
        this.order = order;
    }

    @Override
    public void onReceive(Object message) throws Exception {
        if (message instanceof SomeCommand) {
            // Do something using the order and the account;
        } else if (message instanceof FooCommand) {
            // More stuff
        }
    }
}

@Component
public class SpringExtension extends AbstractExtensionId<SpringExtensionImpl> implements ExtensionIdProvider {

    @Autowired
    private ApplicationContext applicationContext;

    @Override
    public SpringExtensionImpl createExtension(ExtendedActorSystem system) {
        return applicationContext.getBean(SpringExtensionImpl.class);
    }

    @Override
    public ExtensionId<? extends Extension> lookup() {
        return applicationContext.getBean(SpringExtension.class);
    }

}

@Component
public class SpringExtensionImpl implements Extension {

    @Autowired
    private ApplicationContext applicationContext;

    public Props props(String actorBeanName) {
        return Props.create(SpringActorProducer.class, applicationContext, actorBeanName);
    }

}

public class SpringActorProducer implements IndirectActorProducer {

    private final ApplicationContext applicationContext;
    private final String actorBeanName;

    public SpringActorProducer(ApplicationContext applicationContext, String actorBeanName) {
        this.applicationContext = applicationContext;
        this.actorBeanName = actorBeanName;
    }

    @Override
    public Actor produce() {
        return (Actor) applicationContext.getBean(actorBeanName);
    }

    @Override
    public Class<? extends Actor> actorClass() {
        return (Class<? extends Actor>) applicationContext.getType(actorBeanName);
    }

}

现在我的问题是，如何使用自定义构造函数参数实例化actor。我曾考虑过使用工厂或 setter 方法，但我认为这不是一个选择，因为我认为无法访问基础Actor类。非常感谢对此事的任何投入。如果现在清楚了，请发表评论。

PS。如果您认为我的代码有错误或有更好的解决方法，请告诉我!我对Spring和Akka的结合经验很少，因此任何建议都值得赞赏。

最佳答案

您可以将其他参数作为varargs(Object...)传递给SpringExtensionImpl和SpringActorProducer。因此您的代码如下所示:

@Component
public class SpringExtensionImpl implements Extension {

   @Autowired
   private ApplicationContext applicationContext;

   public Props props(String actorBeanName, Object... args) {
       return (args != null && args.length > 0) ?
            Props.create(SpringActorProducer.class,
                    applicationContext,
                    actorBeanName, args) :
            Props.create(SpringActorProducer.class,
                    applicationContext,
                    actorBeanName);
    }
}

public class SpringActorProducer implements IndirectActorProducer {

    private final ApplicationContext applicationContext;
    private final String actorBeanName;
    private final Object[] args;

    public SpringActorProducer(ApplicationContext applicationContext, String actorBeanName) {
        this.applicationContext = applicationContext;
        this.actorBeanName = actorBeanName;
        this.args = null;
    }

    public SpringActorProducer(ApplicationContext applicationContext, String actorBeanName, Object... args) {
        this.applicationContext = applicationContext;
        this.actorBeanName = actorBeanName;
        this.args = args;
    }

    @Override
    public Actor produce() {
        return args == null ?
              (Actor) applicationContext.getBean(actorBeanName):
              (Actor) applicationContext.getBean(actorBeanName, args);
    }

    @Override
    public Class<? extends Actor> actorClass() {
        return (Class<? extends Actor>) applicationContext.getType(actorBeanName);
    }

}

然后，您可以像这样创建Test actor:
SpringExtensionImpl springExtensionImpl;actorSystem.actorOf(springExtensionImpl.create(Test.class, account, order));