使用邮递员,我可以在正文中使用以下json获得正确的响应:
{
"cpu": {
"filters": [
]
}
}
在我的Angular 2服务中,我发布了这样的请求:
import { Injectable } from '@angular/core';
import { Http, Headers, RequestOptions, Response } from '@angular/http';
import { BaseService } from './base.service';
import { Observable } from 'rxjs/Observable';
import { Cpu } from '../entities/cpu';
import { PostObject } from '../entities/post-object';
import { CPU } from '../datasource/database-data';
import 'rxjs/add/operator/map';
@Injectable()
export class CpuService extends BaseService {
postObject: PostObject;
constructor(private http: Http) {
super();
}
getCpus(): void {
this.postObject = new PostObject();
console.log(JSON.stringify(this.postObject));
this.http.post(this.getUrl('/searchCPU'), JSON.stringify(this.postObject))
.subscribe((result: any) =>
console.log(result);
return result
});
}
}`
PostObject:
export class PostObject {
cpu: {
filters: string[]
}
}
当我控制台记录我的postObject对象时,它是空的...?也许
this.postObject = new PostObject();
是错误的..? 最佳答案
如果您要发送类,则类需要一个构造函数。我不知道发送空对象的用例,但是您也可以跳过类并手动创建对象。不过,这不好维护,但是可以通过以下方式实现:
this.postObject = {cpu:{filters:[]}}
如果您要上课,您将有两个:
export class PostObject {
constructor(public cpu: Cpu) {}
}
export class Cpu {
constructor(public filters: string[]) {}
}
并创建一个新的
PostObject
,如下所示:this.postObject = new PostObject(new Cpu([]))
两种方法都能达到您想要的效果,即:
{
"cpu": {
"filters": [
]
}
}