我做了以下特定于IO monad的函数:
memoIO :: MonadIO m => m a -> IO (m a)
memoIO action = do
ref <- newMVar Nothing
return $ do
x <- maybe action return =<< liftIO (takeMVar ref)
liftIO . putMVar ref $ Just x
return x
用法示例:
main :: IO ()
main = do
p <- memoIO $ putStrLn "hello"
p
p
一次打印“
hello
”。我希望(一个小问题)使其在尽可能多的情况下(不仅仅是在IO中)起作用。
我在黑客上发现了stateref,它的代码如下所示:
{-# LANGUAGE FlexibleContexts, FlexibleInstances, MultiParamTypeClasses, Rank2Types, UndecidableInstances #-}
import Data.MRef
class (NewMRef r m a, DefaultMRef r m a, PutMRef r m a, TakeMRef r m a) => MRef r m a
instance (NewMRef r m a, DefaultMRef r m a, PutMRef r m a, TakeMRef r m a) => MRef r m a
memo :: (MRef r m (Maybe a), Monad s) => (forall x. m x -> s x) -> s a -> m (s a)
memo liftFunc action = do
ref <- newDefaultMRef Nothing
return $ do
x <- maybe action return =<< liftFunc (takeDefaultMRef ref)
liftFunc . putDefaultMRef ref $ Just x
return x
有没有比我更好的stateref替代方法或更好的使用方法?
最佳答案
我已经在几个不同的场合重写了一个俗气的MonadRef
类供我个人使用,有人可能在Hackage上有一个,但是我找不到一个不受其他行李困扰的类。
class Monad m => MonadRef m where
type Ref m :: * -> *
newRef :: a -> Ref m a
writeRef :: Ref m a -> -> m ()
readRef :: Ref m a -> m a
instance MonadRef IO where
type Ref IO = IORef
newRef = newIORef
writeRef = writeIORef
readRef = writeIORef
instance MonadRef STM where
type Ref STM = TVar
...
instance MonadRef (ST s) where
type Ref (ST s) = STRef s
...
这样就很容易抽象出您的内存例程(尽管您可能想在此上下文中用
IORef
替换MVar
)。[编辑:澄清的语言]