ID Name FatherID Birthyear
1 Bart NULL 1756
2 Franz 1 1796
3 Josef 2 1835
4 Zohan 3 1887
假设我有这张表,我想知道佐汉是巴特的儿子,如果我把“FatherID”列的值与前面几行的ID进行比较,直到我找到巴特,就可以得到这个表。但是如何比较同一个表中不同行和列的值
最佳答案
您可以自行加入表格:
SELECT s.name AS son_name, f.name AS father_name
FROM mytable s
JOIN mytable f ON s.fatherID = f.id
-- possibly add a where clause with conditions on son/father names