我有两个组件。logincomponent和landingcomponent。我必须在验证用户名和密码后从登录页路由到landingpage。但是我不能访问服务内部的路由器,因为它是全局/页面变量。它显示错误“typeerror:无法读取属性‘router’”。
import {Component} from 'angular2/core';
import { RouteConfig, ROUTER_DIRECTIVES, ROUTER_PROVIDERS, Router } from 'angular2/router';
import {LoginService} from './login.service';
import {NgForm} from 'angular2/common';
@Component({
selector: 'login',
templateUrl: './app/app-components/login/login.html',
styleUrls:['./app/app-components/login/login.css'],
directives: [ROUTER_DIRECTIVES],
providers:[LoginService]
})
export class LoginComponent {
//DECLARATIONS
login={username:"",password:""} ;
active = true;
submitted = false;
router:Router;
constructor(private _loginService: LoginService,private _router: Router) {
this.router = _router;
}
onAuthenticate() {
this.submitted = true;
this._loginService.Login().then( function (loginValues) {
if(loginValues.username=="sampleuser" && loginValues.password=="a"){
this.router.navigate(['LandingPage']);
}
else{
alert("Invalid Username or Password!!");
}
});
}
}
服务函数
import {Injectable} from 'angular2/core';
@Injectable()
export class LoginService {
Login(){
return Promise.resolve(login);
}
}
var login={
username:"sampleuser",
password:"a"
}
最佳答案
您应该在logincomponent中使用这样的arrow-functions:
this._loginService.Login().then( (loginValues) => {
if(loginValues.username=="sampleuser" && loginValues.password=="a"){
this.router.navigate(['LandingPage']);
}
else{
alert("Invalid Username or Password!!");
}
});
这不会改变函数内部的this。否则,这不会指向logincomponent的实例,并且找不到路由器。