我需要选择出现在大多数电影中的演员。
我正在使用sakila数据库1.0:
.mwb (MySQL Workbench): https://www.sendspace.com/file/i0z82j
.sql (schema): https://www.sendspace.com/file/vd3hnu
.sql (data): https://www.sendspace.com/file/gbp9ri
我已经有两个查询
这会选择每个演员n次(n =电影中的出场人数)。
我的查询:
选择actor.first_name,actor.last_name
从演员
INNER JOIN film_actor
开启actor.actor_id = film_actor.actor_id;
结果:
+------------+-------------+
| first_name | last_name |
+------------+-------------+
| PENELOPE |GUINESS | //4 Films in this examle
| PENELOPE |GUINESS |
| PENELOPE |GUINESS |
| PENELOPE |GUINESS |
| NICK |WAHLBERG | //5 Films in this examle
| NICK |WAHLBERG |
| NICK |WAHLBERG |
| NICK |WAHLBERG |
| NICK |WAHLBERG |
| ED |CHASE | //5 Films in this examle
| ED |CHASE |
| ED |CHASE |
| ED |CHASE |
| ED |CHASE |
| JENNIFER |DAVIS | //4 Films in this examle
| JENNIFER |DAVIS |
| JENNIFER |DAVIS |
| JENNIFER |DAVIS |
| BETTE |NICHOLSON | //3 Films in this examle
| BETTE |NICHOLSON |
| BETTE |NICHOLSON |
| ... |... | //Everyother Actor who appeared in a film
+------------+-------------+
它会选择每部影片中的特定演员出演。
我的查询:
选择actor_id,film_id
FROM film_actor
在哪里actor_id = 1;
结果:演员1出现在19部电影中。
+----------+-------- +
| actor_id | film_id |
+----------+---------+
| 1 | 1 |
| 1 | 23 |
| 1 | 25 |
| 1 | 106 |
| 1 | 140 |
| 1 | 166 |
| 1 | 277 |
| 1 | 361 |
| 1 | 438 |
| 1 | 499 |
| 1 | 506 |
| 1 | 509 |
| 1 | 605 |
| 1 | 635 |
| 1 | 749 |
| 1 | 832 |
| 1 | 939 |
| 1 | 970 |
| 1 | 980 |
+----------+---------+
但是我想要的是:
出现在最多电影中的演员:
+------------+---------------+--------+
| first_name | last_name | films |
+------------+---------------+--------+
| NICK | WAHLBERG | 5 |
| ED | CHASE | 5 |
| ... | ... | ... |
+------------+----------------+-------+
非常感谢您的帮助。
谢谢!
最佳答案
我无法在您的数据库上运行查询,但我会这样做:
SELECT count(film_actor.actor_id), actor.first_name, actor.last_name
FROM actor INNER JOIN film_actor ON actor.actor_id = film_actor.actor_id
GROUP BY film_actor.actor_id ;
未经测试
关于mysql - 影片最多的MySQL Sakila Select Actor ,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/42246046/