python - 我使用管理器时，执行反向关系查询的Django发生最大递归深度超出错误

这是代码：

CarSource类

class CarSource(models.Model):
    status = models.CharField(max_length=1, blank=True, null=True)
    dealer = models.ForeignKey(Dealer, blank=True, null=True, \
                  on_delete=models.SET_NULL, related_name='cars', \
                  verbose_name=u'dealer own this car')
    objects = CarSourceManager()

类经销商

class Dealer(models.Model):
    ...

CarSourceManager类：

class CarSourceManager(models.Manager):
    ''' Manage query in CarSource, filter data that was processed successfully.'''
    def get_query_set(self):
        return super(self.__class__, self).get_query_set().filter(status='S')

当我执行此命令时：

from ... import Dealer
d = Dealer.objects.get(id = 2)
d.cars.all()

发生错误如下：

File "/...path..of..error..file../apps/car/managers.py", line 9, in all
return super(self.__class__, self).all().filter(status='S')
File "/...path..of..error..file../apps/car/managers.py", line 9, in all
return super(self.__class__, self).all().filter(status='S')
File "/...path..of..error..file../apps/car/managers.py", line 9, in all
return super(self.__class__, self).all().filter(status='S')
File "/...path..of..error..file../apps/car/managers.py", line 9, in all
return super(self.__class__, self).all().filter(status='S')
File "/...path..of..error..file../apps/car/managers.py", line 9, in all
return super(self.__class__, self).all().filter(status='S')
File "/...path..of..error..file../apps/car/managers.py", line 9, in all
return super(self.__class__, self).all().filter(status='S')
File "/...path..of..error..file../apps/car/managers.py", line 9, in all
return super(self.__class__, self).all().filter(status='S')
RuntimeError: maximum recursion depth exceeded while calling a Python object

我在get_query_set中覆盖了models.Manager的CarSourceManager，显然，它继续递归自称为它。我已经看过Manager的代码，但无法弄清楚，请帮助我。

最佳答案

查看此答案：https://stackoverflow.com/a/18208725/1085511

基本上你不能使用

super(self.__class__, self)

采用

super(CarSourceManager, self)

代替。

相关经理的self.__class__与CarSourceManager不同，因此循环不同。