这是我要测试的代码
public static Map<String, String> JSON2Map(String urlParams) {
String [] params = urlParams.split("&");
Map<String, String> map = new HashMap<String, String>();
for (String param : params) {
String[] kvs= param.split("=");
if ( kvs.length>1)
map.put(kvs[0], kvs[1]);
}
return map;
}
这是我的junit测试:
@Rule
public ExpectedException exception = ExpectedException.none();
@Test
public void JSON2MapTest() throws Exception {
exception.expect(NullPointerException.class);
exception.expectMessage("send null will occur NullPointerException");
JSONUtils.JSON2Map(null);
}
当我运行测试时,它抛出:
java.lang.AssertionError:
Expected: (exception with message a string containing "send null will occur NullPointerException" and an instance of java.lang.NullPointerException)
got: java.lang.NullPointerException
如果我注释掉
//exception.expectMessage?(....)
,它将通过。exception.expectMessage
会怎样? 最佳答案
测试失败的原因是:
exception.expectMessage("send null will occur NullPointerException");
该代码声明断言返回的消息,但没有异常。
Here是如何编写代码并测试预期消息的示例:
public class Person {
private final int age;
/**
* Creates a person with the specified age.
*
* @param age the age
* @throws IllegalArgumentException if the age is not greater than zero
*/
public Person(int age) {
this.age = age;
if (age <= 0) {
throw new IllegalArgumentException("Invalid age:" + age);
}
}
}
考试:
public class PersonTest {
@Rule
public ExpectedException exception = ExpectedException.none();
@Test
public void testExpectedException() {
exception.expect(IllegalArgumentException.class);
exception.expectMessage(containsString("Invalid age"));
new Person(-1);
}
}