java - 用JAXB读取xml

我有这样的XML

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<data-set>
    <record>
        <TARIH>data</TARIH>
        <GUNLER>data</GUNLER>
        <YEMEK1>data</YEMEK1>
        <YEMEK2>data</YEMEK2>
    </record>
    <record>
        <TARIH>data</TARIH>
        <GUNLER>data</GUNLER>
        <YEMEK1>data</YEMEK1>
        <YEMEK2>data</YEMEK2>
    </record>
</data-set>

我想用Java中的JAXB解析它。这是我的DataSet类。

@XmlRootElement(name="data-set")
@XmlAccessorType(XmlAccessType.FIELD)
public class DataSet {
    @XmlElement(name="record")
    private List<Record> records = null;
    public List<Record> getRecords(){
        return records;
    }

    public void setRecords(List<Record> records){
        this.records = records;
    }
}

这是我的记录课。

@XmlRootElement(name="record")
@XmlAccessorType(XmlAccessType.FIELD)
public class Record {
    String TARIH,GUNLER,YEMEK1,ANAYEMEK1,ANAYEMEK2,YEMEK3,YEMEK4,SALATBAR1,SALATBAR2,SALATBAR3,SALATBAR4,SALATBAR5;

    //getters and setters//

我尝试这样的事情。

public class Main {
    public static void main(String[] args) throws JAXBException {
        File file = new File("C:/Users/EMRE/Desktop/YEMEKHANE DATABASE/morning.xml");
        JAXBContext jaxbcontext = JAXBContext.newInstance(Record.class);
        Unmarshaller jaxbunmarshaller = jaxbcontext.createUnmarshaller();
        Record record = (Record)jaxbunmarshaller.unmarshal(file);

        System.out.println(record.getTARIH());
    }
}

我遇到这样的错误。

Exception in thread "main" javax.xml.bind.UnmarshalException: unexpected element (uri:"", local:"data-set"). Expected elements are <{}record>

我怎样才能解决这个问题？谢谢。

最佳答案

使用DataSet类创建上下文。

JAXBContext jaxbcontext = JAXBContext.newInstance(DataSet.class);

也许您还需要添加Record（不确定）：

@XmlSeeAlso({Record.class})
public class DataSet {...}

但是我认为即使没有它也可能会起作用。

或者，您可以执行以下操作：

JAXBContext jaxbcontext = JAXBContext.newInstance(DataSet.class, Record.class);

还有其他一些基于软件包名称的context path替代方案。如果您手动编写类，不是那么简单。