.Net 中是否有任何类(函数)可以执行此操作:
如果s1 = " I have a black car" and s2 = "I have a car that is small";
int matchingProcentage = matchingFunction(s1,s2);
matchingProcentage == 70% <-- just as an example value :)
最佳答案
这是一个很好的方法!
Levenshtein Distance
关于c# - 提前进行C#字符串比较,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/7031524/