我需要使用Secure.getString()获取设备ID
我正在使用上下文
public static String getDeviceId(Context context) {
String currentDeviceId = SharedPreferencesUtil.getCurrentDeviceId();
if (currentDeviceId == null) {
context = Secure.getString(context.getContentResolver(), "android_id");
if (context == null || context.trim().isEmpty() || "9774d56d682e549c".equalsIgnoreCase(context)) {
context = Build.SERIAL;
if (context == null || context.trim().isEmpty() != null) {
context = UUID.randomUUID().toString();
} else {
context = Build.SERIAL;
}
}
if ("unknown".equals(context)) {
context = Build.SERIAL;
if (context == null || context.trim().isEmpty() != null) {
context = UUID.randomUUID().toString();
} else {
context = Build.SERIAL;
}
}
secondDeviceId = context;
此行显示以下错误
context = Secure.getString(context.getContentResolver(), "android_id");
不兼容的类型。
需要:
android.content.Context
发现:
java.lang.String
最佳答案
根据@vlumi注释和调试,我发现以下代码可以解决此问题。
现在已修复,只需要用字符串替换上下文即可。
public static String getDeviceId(Context paramContext) {
String localObject = SharedPreferencesUtil.getCurrentDeviceId();
if (localObject == null) {
String str1 = Settings.Secure.getString(paramContext.getContentResolver(), "android_id");
if ((str1 == null) || (str1.trim().isEmpty()) || ("9774d56d682e549c".equalsIgnoreCase(str1)))
{
String str2 = Build.SERIAL;
if ((str2 != null) && (!str2.trim().isEmpty())) {
str1 = Build.SERIAL;
} else {
str1 = UUID.randomUUID().toString();
}
}
if ("unknown".equals(str1))
{
String str3 = Build.SERIAL;
if ((str3 != null) && (!str3.trim().isEmpty())) {
str1 = Build.SERIAL;
} else {
str1 = UUID.randomUUID().toString();
}
}
secondDeviceId = str1;