javascript - JavaScript-为什么我的parseInt返回NaN？

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var bucketId = $.cookie('bucketId');
console.log(bucketId);

var bucketIdNumber = parseInt(bucketId, 10);
console.log("bucketIdNumber " + bucketIdNumber);

在关于bucketId的代码中，返回“ 17”。
那么，为什么当我parseInt bucketId时会得到NaN？

最佳答案

如果我正确理解这一点，则上面的代码等效于：

var bucketId = '"17"';
console.log(bucketId);

var bucketIdNumber = parseInt(bucketId, 10);
console.log("bucketIdNumber " + bucketIdNumber);

在这种情况下，bucketIdNumber确实返回NaN。您将需要进一步解析此cookie，并删除所有内部引号。