h = soup.findAll("div", {"id": "products"})
for row in h:
    b = row.findAll("div", {"class": "gd-row"})
    for a in b:
        c = a.findAll("div", {"class": "gd-col"})
        for d in c:
            e = d.findAll("div", {"class": "product-unit"})
            for f in e:
                g = f.findAll("div", {"class": "pu-details"})
                for h in g:
                    i = h.findAll("div", {"class": "pu-title"})
                    for k in i:
                        l = k.findAll('a')
                        for z in l:
                            text = z.get('href')

                            title = str(z.get_text().strip())
                            urldict.update({counter: text})
                            print (str(counter) + ')' + title)

                            titlelist.append(title)

                            counter = counter + 1


print ("\nSeems we found more than one same mobile type, help us by selecting appropiate model \n")
user_choice = input("\nEnter your choice (number) which matches exactly:")
url_from_search = "http://www.xyzabc.com{}".format(
    urldict.get(user_choice).split('&')[0])


谁能帮我这个?我正在尝试在beautifulsoup的帮助下进行html解析。上面给出的代码抛出了属性错误。可能是什么问题?如果可以的话请帮助我。

最佳答案

显然,user_choice键不在urldict词典中,并且urldict.get(user_choice)返回None。假设您使用的是Python 3,并且urldict键是整数,则需要在进行查找之前将输入数字转换为整数:

user_choice = int(input("\nEnter your choice (number) which matches exactly:"))
url_from_search = "http://www.acxcs.com{}".format(
    urldict.get(user_choice).split('&')[0])


另外,您可能应该更好地处理“丢失密钥”的情况。例如:

user_choice = int(input("\nEnter your choice (number) which matches exactly:"))
if user_choice not in urldict:
    print("Error, the number is not valid")
else:
    url_from_search = "http://www.acxcs.com{}".format(urldict[user_choice].split('&')[0])

10-05 21:29