合并排序中出现堆栈溢出错误

合并排序中出现堆栈溢出错误

合并排序中出现堆栈溢出错误不知道为什么。

//BAD CODE BAD CODE
public static void main(String[] args) {
    int[] S = {3,4,6,2,5,3,7};
    mergesort(S, 1, 5);
    System.out.println(S);
}

public static void mergesort(int[] S, int left, int right){
    if (right <= 1) { return; }
    int mid = (right + left) / 2;
    mergesort (S, left, mid);
    mergesort (S, mid+1, right);
    merge(S, left, mid, right);
}

public static void merge(int[] S, int left, int mid, int right){
    int i, j;
    int[] aux = new int[S.length];

    for (i = mid+1; i > left; i--) {aux[i-1] = S[i-1];}
    for (j = mid; j < right; j++) {aux[right+mid-j] = S[j+1];}
    for (int k = left; k <= right; k++){
        if (aux[j] < aux[i]) {
            S[k] = aux[j--];
        } else{
            S[k] = aux[i++];
        }
    }
}
//END OF BAD CODE

更新
谢谢你的快速反应,我让它工作,并提出了一些修改建议。复制粘贴,试试看:
//GOOD CODE
package longest_sequence_proj;
import java.util.*;

public class MergeTest {

/**
 * @param args
 */
public static void main(String[] args) {
    int[] S = {3,4,6,2,5,3,7};

    mergesort(S, 0, 6);

    System.out.println(Arrays.toString(S));

}



public static void mergesort(int[] S, int left, int right){
    if (right <= left) { return; }
    int mid = (right + left) / 2;
    mergesort (S, left, mid);
    mergesort (S, mid+1, right);
    merge(S, left, mid, right);

    }

public static void merge(int[] S, int left, int mid, int right){
    int i, j;
    int[] aux = new int[S.length];

    for (i = mid+1; i > left; i--) {aux[i-1] = S[i-1];}
    for (j = mid; j < right; j++) {aux[right+mid-j] = S[j+1];}
    for (int k = left; k <= right; k++){
        if (aux[j] < aux[i]) {
            S[k] = aux[j--];
        } else{
            S[k] = aux[i++];
        }
    }
}
}

最佳答案

你的停止条款错了:

 if (right <= 1) { return; }

当使用的部分数组的大小小于1时,实际上需要停止,因此您可能要查找:
if (right - left <= 1) { return; }

作为旁注:
System.out.println(S);

我想这不是你想要的(它不打印数组,而是对象的标识符…)
要打印数组,请使用:
System.out.println(Arrays.toString(S));

10-05 21:22