我在AWS DynamoDB中有一个名为accountantHistoric的表。它具有一个主分区键(id)和一个主排序键(tenant_id)。我还创建了另一个索引,称为“ ExpirationDate”。该索引的排序键是“ expirationDate”(String)属性。我想要的是:基于storeId(此字段不是键)获取itens,并根据“ expirationDate”(从最新到最旧)以降序获取tenant_id。我也正在分页。
我正在尝试下面的代码,但是它没有以降序返回。
我要改变什么?
谢谢你们!
public AccountantEmailHistoricInfo getHistoric(String storeId, int page, int countReg, int fixedPage) {
Condition conditionStoreId = new Condition().withComparisonOperator(ComparisonOperator.EQ)
.withAttributeValueList(new AttributeValue().withS(storeId));
Condition conditionTenantId = new Condition().withComparisonOperator(ComparisonOperator.EQ)
.withAttributeValueList(new AttributeValue().withS(TenantIdentifierLocalThread.getTenantIdentifier()));
final DynamoDBScanExpression scanPageExpression = new DynamoDBScanExpression()
.withFilterConditionEntry("tenant_id", conditionTenantId)
.withFilterConditionEntry("storeId", conditionStoreId)
.withIndexName("ExpirationDate")
.withLimit(countReg);
List<AccountantEmailHistoric> accountantEmailHistoricList = new ArrayList<>();
int i = 0;
do {
ScanResultPage<AccountantEmailHistoric> scanPage = mapper.scanPage(AccountantEmailHistoric.class, scanPageExpression);
scanPageExpression.setExclusiveStartKey(scanPage.getLastEvaluatedKey());
if (i == page) {
accountantEmailHistoricList.addAll(scanPage.getResults());
}
i++;
} while (scanPageExpression.getExclusiveStartKey() != null);
final DynamoDBScanExpression scan = new DynamoDBScanExpression()
.withFilterConditionEntry("tenant_id", conditionTenantId)
.withFilterConditionEntry("storeId", conditionStoreId);
AccountantEmailHistoricInfo info = new AccountantEmailHistoricInfo(accountantEmailHistoricList);
info.setPage(fixedPage);
info.setTotalRecords(mapper.scan(AccountantEmailHistoric.class, scan).size());
return info;
}
最佳答案
您需要query,而不是扫描。然后,您可以指示ScanIndexForward
设置为false。