python - 如何通过URL过滤flask-peewee中的查询？

我想通过flask-peewee运行以下查询，

merchant_name像“海边％”

SELECT *
FROM  `merchant_details`
WHERE  `merchant_name` LIKE  'seaside%'

这是以下URL的返回JSON，我需要过滤merhcnat_name
http://www.XXXXX.com/api/merchant_details/

http://www.XXXXX.com/api/merchant_details/?merchant_name__like=seaside（这不起作用）

{
  "meta": {
    "model": "merchant_details",
    "next": "",
    "page": 1,
    "previous": ""
  },
  "objects": [
    {
      "merchant_name": "Seaside Grill",
      "city": "Santa Monica ",
      "zipcode": "90401",
      "long": "-118.4884742",
      "phone": "3102399844",
      "state": "CA",
      "updated_on": "2013-11-07 01:14:42",
      "lat": "34.0189893",
      "street_1": "406 Broadway",
      "street_2": "1",
      "merchant_id": "1",
      "id": "2"
    },
{
  "merchant_name": "Jack n'  Jill's",
  "city": "Santa Monica",
  "zipcode": "90401",
  "long": "-118.4937635",
  "phone": "3109873733",
  "state": "CA",
  "updated_on": "2013-11-08 08:20:29",
  "lat": "34.0173215",
  "street_1": "510 Santa Monica Blvd",
  "street_2": "1",
  "merchant_id": "48",
  "id": "32"
}
  ]
}

最佳答案

您应该像这样编码网址：

?merchant_name__like=seaside%25

您可以通过urllib.urlencode({'merchant_name__like': 'seaside%'})获得编码的查询字符串，在SQL中?merchant_name__like=seaside表示LIKE seaside。