3D 中的 Python 频谱图(如 matlab 的频谱图函数)

我的问题如下:

我拥有频谱图 ( scipy.fftpack.fft ) 所需的所有值。我想在 python 中创建一个 3D 频谱图。

在 MATLAB 中，这是一项非常简单的任务，而在 Python 中似乎要复杂得多。我尝试过 mayavi、3D 绘图 matplotlib，但我还没有设法做到这一点。

谢谢

我的代码:

import numpy as np
import pandas as pd
import numpy as np
from scipy import signal
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
from matplotlib.collections import PolyCollection

fs = 11240.
t = 10
time = np.arange(fs*t) / fs
frequency = 1000.
mysignal = np.sin(2.0 * np.pi * frequency * time)

nperseg = 2**14
noverlap = 2**13
f, t, Sxx = signal.spectrogram(mysignal, fs, nperseg=nperseg,noverlap=noverlap)

myfilter = (f>800) & (f<1200)

fig,ax = plt.subplots()

plt.pcolormesh(t, f[myfilter], 10*np.log10(Sxx[myfilter, :]), cmap='jet')
plt.show()

fig = plt.figure()
ax = fig.gca(projection='3d')
x = []
y = []

for counter,i in enumerate(f):
    x.append(np.array([i for k in t]))
    y.append(t)

ax.plot_surface(np.array(x), np.array(y), 10.0*np.log10(Sxx), cmap=cm.coolwarm)
plt.show()

类似的未回答问题:How to convert a spectrogram to 3d plot. Python

在 python 中所需的图，如 Matlab 的图(这里的最后一个图: https://www.mathworks.com/help/signal/ref/spectrogram.html )

最佳答案

你只需要让你的数组处于正确的形状:

fs = 11240.
t = 10
time = np.arange(fs*t) / fs
frequency = 1000.
mysignal = np.sin(2.0 * np.pi * frequency * time)

nperseg = 2**14
noverlap = 2**13
f, t, Sxx = signal.spectrogram(mysignal, fs, nperseg=nperseg,noverlap=noverlap)

myfilter = (f>800) & (f<1200)

f = f[myfilter]
Sxx = Sxx[myfilter, ...]

fig = plt.figure()
ax = fig.gca(projection='3d')

ax.plot_surface(f[:, None], t[None, :], 10.0*np.log10(Sxx), cmap=cm.coolwarm)
plt.show()

关于3D 中的 Python 频谱图(如 matlab 的频谱图函数)，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/56788798/