iphone - 无法识别的选择器发送到类0x51e8'

当我尝试将uitableview中的tableView:didSelectRowAtIndexPath:方法的uitextfeild值传递给nsobject类时出现此错误，但是当我单击已编码为传递uitextfield值的uitableviewcell时，收到以下错误。

//DBAccess.h

    @interface DBAccess : NSObject {

        NSString *receiveCodeText;

    }

    @property (nonatomic, retain) IBOutlet NSString *receiveCodeText;

- (NSMutableArray *) getAllMakes;
    - (void) setPassCode:(NSString *)theCode;

//DBAccess.m

//...
//Need to set my string here..
- (void)setPassCode:(NSString *)theCode{
    receiveCodeText = theCode;
}
//...
- (NSMutableArray *)getAllMakes{
//...
const char *value = [receiveCodeText cStringUsingEncoding:NSUTF8StringEncoding]; //reciveCodeText is set in RootViewController and passed to value here
    [receiveCodeText release];
    sqlite3_bind_text(statement, 1, value, -1, SQLITE_TRANSIENT);

//....
}

//viewController.m

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {

    searchTableViewController *searchTable = [[searchTableViewController alloc] initWithNibName:@"searchTableViewController" bundle:nil];

    switch (indexPath.row) {
        case 1: {
            searchTable.editedFieldName = @"Make";
            //Pass code number over to DBAccess class
            [DBAccess setPassCode:codeText.text];
        } break;
        case 2: {
            searchTable.editedFieldName = @"Mod";
        } break;
        case 3: {
            searchTable.editedFieldName = @"Method";
        } break;
    }

    [self.navigationController pushViewController:searchTable animated:YES];
    [searchTable release];
}

这就是我得到的错误。

> 2011-06-13 13:05:33.433
> Code1.6[1318:207] +[DBAccess
> setPassCode:]: unrecognized selector
> sent to class 0x51e8 2011-06-13
> 13:05:33.477 Code1.6[1318:207] ***
> Terminating app due to uncaught
> exception
> 'NSInvalidArgumentException', reason:
> '+[DBAccess setPassCode:]:
> unrecognized selector sent to class
> 0x51e8'
> *** Call stack at first throw: (  0   CoreFoundation
> 0x00e45be9 __exceptionPreprocess + 185
>   1   libobjc.A.dylib
> 0x00f9a5c2 objc_exception_throw + 47
>   2   CoreFoundation
> 0x00e477bb +[NSObject(NSObject)
> doesNotRecognizeSelector:] + 187  3
> CoreFoundation
> 0x00db7366 ___forwarding___ + 966     4
> CoreFoundation
> 0x00db6f22 _CF_forwarding_prep_0 + 50
>   5   Code1.6
> 0x000028ff -[RootViewController
> tableView:didSelectRowAtIndexPath:] +
> 253   6   UIKit
> 0x00331794 -[UITableView
> _selectRowAtIndexPath:animated:scrollPosition:notifyDelegate:]
> + 1140    7   UIKit                               0x00327d50 -[UITableView
> _userSelectRowAtPendingSelectionIndexPath:]
> + 219     8   Foundation                          0x0003a7f6 __NSFireDelayedPerform +
> 441   9   CoreFoundation
> 0x00e26fe3

> __CFRUNLOOP_IS_CALLING_OUT_TO_A_TIMER_CALLBACK_FUNCTION__
> + 19  10  CoreFoundation                      0x00e28594 __CFRunLoopDoTimer + 1220
>   11  CoreFoundation
> 0x00d84cc9 __CFRunLoopRun + 1817  12
> CoreFoundation
> 0x00d84240 CFRunLoopRunSpecific + 208
>   13  CoreFoundation
> 0x00d84161 CFRunLoopRunInMode + 97    14
> GraphicsServices
> 0x016e7268 GSEventRunModal + 217  15
> GraphicsServices
> 0x016e732d GSEventRun + 115   16  UIKit
> 0x002ca42e UIApplicationMain + 1160
>   17  Code1.6
> 0x0000230c main + 102     18  Code1.6
> 0x0000229d start + 53 ) terminate
> called after throwing an instance of
> 'NSException'

最佳答案

setPassCode似乎是一个类实例方法，而不是静态方法，但是您尝试将其作为静态方法访问，必须像这样声明yur方法，以使其成为静态方法

+(void)setPassCode....

您的程序崩溃，因为您是在类本身而不是类的实例上调用方法。
希望这可以帮助

关于iphone - 无法识别的选择器发送到类0x51e8'，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/6325945/