c++ - C++复制指针

我在弄清楚复制指针的语法时遇到麻烦。

我将如何制作theVar2=theVar？

Struct MyStructureType {
    double* theVar2;
}

MyStructureType* myStruct;
double* theVar;

theVar = malloc(sizeof(double));


myStruct->theVar2 = theVar; //segfaults

最佳答案

拳头为MyStructureType分配内存，然后在其中使用data member。

MyStructureType* myStruct = new MyStructureType();
double* theVar = new double();
myStruct->theVar2 = theVar;