我有一个需要填充并写入磁盘的结构(实际上有几个)。
一个例子是:
byte-6
bit0 - original_or_copy
bit1 - copyright
bit2 - data_alignment_indicator
bit3 - PES_priority
bit4-bit5 - PES_scrambling control.
bit6-bit7 - reserved
在C语言中,我可能会执行以下操作:
struct PESHeader {
unsigned reserved:2;
unsigned scrambling_control:2;
unsigned priority:1;
unsigned data_alignment_indicator:1;
unsigned copyright:1;
unsigned original_or_copy:1;
};
有什么方法可以在C#中做到这一点,从而使我能够使用结构取消引用点运算符访问这些位?
对于两个结构,我只需要包装访问器函数中的位移即可。
我有大量的结构以这种方式处理,因此我正在寻找更易于阅读和编写的东西。
最佳答案
我可能会使用属性将某些东西组合在一起,然后使用一个转换类将适当地归因于结构的结构转换为位域基元。就像是...
using System;
namespace BitfieldTest
{
[global::System.AttributeUsage(AttributeTargets.Field, AllowMultiple = false)]
sealed class BitfieldLengthAttribute : Attribute
{
uint length;
public BitfieldLengthAttribute(uint length)
{
this.length = length;
}
public uint Length { get { return length; } }
}
static class PrimitiveConversion
{
public static long ToLong<T>(T t) where T : struct
{
long r = 0;
int offset = 0;
// For every field suitably attributed with a BitfieldLength
foreach (System.Reflection.FieldInfo f in t.GetType().GetFields())
{
object[] attrs = f.GetCustomAttributes(typeof(BitfieldLengthAttribute), false);
if (attrs.Length == 1)
{
uint fieldLength = ((BitfieldLengthAttribute)attrs[0]).Length;
// Calculate a bitmask of the desired length
long mask = 0;
for (int i = 0; i < fieldLength; i++)
mask |= 1 << i;
r |= ((UInt32)f.GetValue(t) & mask) << offset;
offset += (int)fieldLength;
}
}
return r;
}
}
struct PESHeader
{
[BitfieldLength(2)]
public uint reserved;
[BitfieldLength(2)]
public uint scrambling_control;
[BitfieldLength(1)]
public uint priority;
[BitfieldLength(1)]
public uint data_alignment_indicator;
[BitfieldLength(1)]
public uint copyright;
[BitfieldLength(1)]
public uint original_or_copy;
};
public class MainClass
{
public static void Main(string[] args)
{
PESHeader p = new PESHeader();
p.reserved = 3;
p.scrambling_control = 2;
p.data_alignment_indicator = 1;
long l = PrimitiveConversion.ToLong(p);
for (int i = 63; i >= 0; i--)
{
Console.Write( ((l & (1l << i)) > 0) ? "1" : "0");
}
Console.WriteLine();
return;
}
}
}
产生预期的... 000101011。当然,它需要更多的错误检查和更精巧的键入,但是(我认为)该概念是合理的,可重用的,并且可以让您轻松打出一打维护的结构。
亚当
关于c# - C#中的位字段,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/14464/