c++ - 在OpenCV中从RGB转换为YUYV

有没有办法从RGB转换为YUYV(YUY 4:2:2)格式？我注意到，OpenCV具有反向操作，但是由于某些原因，RGB没有到YUYV。也许有人可以指向执行此操作的代码(即使在OpenCV库之外)？

更新

我发现libyuv库可以通过将BGR转换为ARGB，然后将ARGB转换为YUY2格式来实现此目的(希望这与YUYV 4:2:2相同)。但这似乎不起作用。您是否知道yuyv缓冲区的尺寸/类型应该是什么样？它的步伐如何？

为了澄清YUYV和YUY2是相同的格式(如果有帮助的话)。

更新2
这是我使用libyuv库的代码:

  Mat frame;
  // Convert original image im from BGR to BGRA for further use in libyuv
  cvtColor(im, frame, CVX_BGR2BGRA);
  // Actually libyuv requires ARGB (i.e. reverse of BGRA), so I swap channels here
  int from_to[] = { 0,3, 1,2, 2,1, 3,0 };
  mixChannels(&frame, 1, &frame, 1, from_to, 4);
  // This is the most confusing part. Not sure what argb_stride suppose to be - length of a row in bytes or size of single value in the array?
  const uint8_t* argb_data = frame.data;
  int argb_stride = 8;

  // Also it is not clear what size of yuyv frame should be since we duplicate one Y
  Mat yuyv(frame.rows, frame.cols, CVX_8UC2);
  uint8_t* yuyv_data = yuyv.data;
  int yuyv_stride = 16;
  // Do actual conversion
  libyuv::ARGBToYUY2(argb_data, argb_stride, yuyv_data, yuyv_stride,
  frame.cols, frame.rows);
  // Then I feed yuyv_data to video stream buffer and see green or purple image instead of video stream.

更新3

  Mat frame;
  cvtColor(im, frame, CVX_BGR2BGRA);

  // ARGB
  int from_to[] = { 0,3, 1,2, 2,1, 3,0 };
  Mat rgba(frame.size(), frame.type());
  mixChannels(&frame, 1, &rgba, 1, from_to, 4);
  const uint8_t* argb_data = rgba.data;
  int argb_stride = rgba.cols*4;

  Mat yuyv(rgba.rows, rgba.cols, CVX_8UC2);
  uint8_t* yuyv_data = yuyv.data;
  int yuyv_stride = width * 2;
  int res = libyuv::ARGBToYUY2(argb_data, argb_stride, yuyv_data, yuyv_stride, rgba.cols, rgba.rows);

最佳答案

看来，尽管该方法称为ARGBToYUY2，但它需要 channel 的BGRA顺序(不是反向的)。

关于c++ - 在OpenCV中从RGB转换为YUYV，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/39876798/