java - 我该如何向用户询问一些内容，然后保存答案并再次重复询问相同的问题

好的，下面的代码（我是新手，请多多包涵）我希望能够向用户提问：

System.out.println("Will the customer be adding any options to the order?");
System.out.println("1. Bed Frame ($39.99)");
System.out.println("2. Pillows ($59.99)");
System.out.println("3. Blankets ($129.99)");
System.out.println("4. No Options added. Enter No");

客户将回答1-4，然后循环浏览，询问客户是否要添加其他内容/您确定不希望添加任何内容。如果没有，则将客户发送到其他班级（更多问题） 。如果是，则再次询问顾客相同的“顾客....”问题。
客户添加让我们说出第1项，然后遍历一个循环，并询问客户是否要添加其他内容/您确定不希望添加任何内容。如果是，则再次询问顾客相同的“顾客....”问题。用户回答完问题后，答案将被保存并打印在writeOutput（）行中，以及您添加的产品的名称和价格。


我知道这是一个循环，但我不知道如何实现这种循环。谁能帮助我并填补空白？谢谢。下面是完整的代码

import java.util.Scanner;
public class addons

{

    private int Option;
    private String Bed_Frame, Pillows, Blankets, No_Options_Added;
    private String Name;
    private double Price;
    public void readInput()
    {

        Scanner keyboard = new Scanner(System.in);
        System.out.println("Will the customer be adding any options to the order?");
         System.out.println("1. Bed Frame ($39.99)");
      System.out.println("2. Pillows ($59.99)");
         System.out.println("3. Blankets ($129.99)");
         System.out.println("4. No Options added. Enter No");
        Option = keyboard.nextInt();

       switch (Option)
            {
                case 1:
                   Name = "Bed Frame";
                    Price = 39.99;
                    break;
                case 2:
                   Name = "Pillows";
                   Price = 59.99;
                    break;
                 case 3:
                   Name = "Blankets";
                   Price = 129.99;
                    break;
                 case 4:
                 Name = "No Options Added";
                 System.out.println("No options added");
                   Price = 0;
                    break;
            }
    }

    public void writeOutput()
    {
        System.out.println(Name);
    }

}

最佳答案

只需添加一个while(true) { ... }块，就可以在问题后添加条件-如果答案是“是”，则使用break（不在切换用例的块中！）完成重复循环：

 public void readInput() {

        Scanner keyboard = new Scanner(System.in);
        while (true) {  //ADDED THE WHILE LOOP
           System.out.println("Will the customer be adding any options to the order?");
           System.out.println("1. Bed Frame ($39.99)");
           System.out.println("2. Pillows ($59.99)");
           System.out.println("3. Blankets ($129.99)");
           System.out.println("4. No Options added. Enter No");
           Option = keyboard.nextInt();
           switch (Option)
              {
               case 1:
                 Name = "Bed Frame";
                 Price = 39.99;
                 break;
               case 2:
                 Name = "Pillows";
                 Price = 59.99;
                 break;
               case 3:
                 Name = "Blankets";
                 Price = 129.99;
                 break;
               case 4:
                 Name = "No Options Added";
                 System.out.println("No options added");
                 Price = 0;
                 break;
            }

      //ADDED EXIT POINT WHEN TO EXIT:
      System.out.println("Is that All?");
      //read an answer
      if (*answer was yes*) break;

      } //ADDED A CLOSING BLOCK
}

阅读答案并确定应该满足的条件是一项练习-因为这似乎是一个教程作业，我不想破坏乐趣！ :)