我有两张这样的桌子
个人资料回答
+---------+------------+
| id | class_name |
+---------+------------+
| 1 | Class 1 |
| 2 | Class 2 |
| 3 | Class 1 |
+---------+------------+
教育
+---------+--------------------+------------+
| id | profile_answers_id | sample |
+---------+--------------------+------------+
| 1 | 1 | 1234 |
| 2 | 1 | 2334 |
| 3 | 1 | 3434 |
+---------+------------+--------------------+
我查了一下,
select educations.profile_answer_id, GROUP_CONCAT(educations.sample) from educations
LEFT JOIN profile_answers ON educations.profile_answers_id = profile_answers.id
我得到了
+--------+--------------------+-------------+
| id | sample |
+---------+--------------------+------------+
| 1 | 1234,2334,3434 |
+---------+------------+--------------------+
我真的想,
+--------+--------------------+-------------+
| id | sample |
+---------+--------------------+------------+
| 1 | 1234,2334,3434 |
| 2 | NULL |
| 3 | NULL |
+---------+------------+--------------------+
最佳答案
SELECT id,IFNULL(samples,'NULL') sample FROM
(
SELECT
AA.id,
GROUP_CONCAT(DISTINCT BB.sample) samples
FROM
profile_answers AA LEFT JOIN educations BB
ON AA.id = BB.profile_answers_id
GROUP BY AA.id
) A;
关于mysql - 在group_concat中包含空结果,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/14820298/