c++ - while循环的两个条件。我怎么了

我有一个问题。除了以下几行，这里的所有内容似乎都可以正常工作：

} while (OneMoreTime != 'y' || OneMoreTime != 'n');

完整代码；

#include <iostream>
using namespace std;


int main()
{
int ARRAY_LENGTH = 5;
int MyArray[ARRAY_LENGTH] = {1, 2, 3, 4, 5};

cout << "Values in the array: " << ARRAY_LENGTH << endl;

for (char OneMoreTime = '\0'; OneMoreTime = 'n'; )
{

    int WhichNumber = ARRAY_LENGTH;
    do
    {
        cout << "What numbers from the array do you want to see, counting backwards? ";
        cin >> WhichNumber;
    } while ((WhichNumber > ARRAY_LENGTH) || (WhichNumber <= 0));


    //calculating the correct position in the array (from start)
    int Number2Print = ARRAY_LENGTH - WhichNumber;


    //printing
    cout << "The number is: " << MyArray[Number2Print] << endl;


    //continue?
    do
    {
        cout << "One more time? (y/n) ";
        cin >> OneMoreTime;
    } while (OneMoreTime != 'y' || OneMoreTime != 'n');

}

return 0;
}

我得到的是，第一次成功打印后，它不断询问“再过一次？（y / n）”。如果我只使用一种条件，它将起作用（但那还不够）。

最佳答案

该条件将始终为true，因为OneMoreTime不能同时等于n和y。您可能的意思是使用&&（和）

while (OneMoreTime != 'y' && OneMoreTime != 'n');