我有一个表达式,我想再插入一个节点。我发现了this SO question类似的问题,该问题在表达式的末尾添加了属性。
我对Expressions还是很陌生,我不知道在节点之间这样做。
我做了这个简单的控制台测试应用程序,以显示我遇到的问题:
public class Program
{
private static void Main()
{
var provider = new Provider<Foo>();
var foo = new Foo {Label = "myLabel", Owner = "Me"};
provider.AddData(foo);
provider.AddExpression(f => f.Label);
// This writes: f => f.Label
Console.WriteLine(provider.OriginalExpression.ToString());
// This should write: f => f.WrappedData.Label
// At the moment it writes: NULL
Console.WriteLine(provider.WrapperExpression == null ? "NULL" : provider.WrapperExpression.ToString());
Console.ReadKey();
}
}
public class Foo
{
public string Label { get; set; }
public string Owner { get; set; }
}
public class Wrapper<T> where T : class
{
public string Id { get; set; }
public T WrappedData { get; set; }
}
public class Provider<T> where T : class
{
public Wrapper<T> _internalWrapper = new Wrapper<T>();
// The expression for the Property when using T (i.e. Foo)
public Expression<Func<T, string>> OriginalExpression { get; private set; }
// The expression for the Property when using _internalWrapper
public Expression<Func<Wrapper<T>, string>> WrapperExpression { get; private set; }
public void AddData(T data)
{
_internalWrapper = new Wrapper<T> { WrappedData = data, Id = "myId" };
}
public void AddExpression(Expression<Func<T, string>> valueExpression)
{
OriginalExpression = valueExpression;
BuildWrapperExpression();
}
private void BuildWrapperExpression()
{
// HERE IS THE PROBLEM:
// Here I have to insert the node "WrappedData" in the OriginalExpression and save it as WrapperExpression
// So {f => f.Label} must result into {f => f.WrappedData.Label}
// It should work as well for deeper nodes. I.e. when OriginalExpression is something like {f => f.Bar.Prop2.Label}
}
}
我已经在BuildWrapperExpression()方法中尝试过查看版本,但没有一个版本提供
f => f.WrappedData.Label
。我得到类似
f => Invoke(value (ConsoleApplication1.Provide1+<>c__DisplayClass1[ConsoleApplication1.Foo]).lambda, f.WrappedData)
或x => Invoke(f => f.Label, Invoke(e => e.WrappedData, x))
对于我来说,表达式的进一步使用必须是
x => x.WrappedData.Label
非常感谢
最佳答案
您不能简单地:
private void BuildWrapperExpression()
{
var lambda = OriginalExpression.Compile();
WrapperExpression = x => lambda(x.WrappedData);
}
或者,您可以实现一个ExpressionVistor。检查马克的答案:https://stackoverflow.com/a/9132775/1386995